
#1
Mar2306, 12:49 PM

HW Helper
PF Gold
P: 1,198

For a current loop, the magnetic dipole moment is defined as [tex]i \int d\vec{a}[/tex]
Now, if I'm given a surface current 'K', how can I find the magnetic dipole moment? For example, if a disc of surface charge [itex] \sigma [/tex] is rotating with angular velocity [itex] \omega [/tex], what is it's magnetic dipole moment? I thought about taking the dipole term from the multipole expansion of the magnetic vector potential, and then trying to separate it into something dependent on current distribution, and something dependent on the point where I'm trying to find the potential, could lead to an expression for m. But I'm getting nowhere that way. So, is it possible to get a term for m in terms of K (and maybe r' ?) ,analogous to a closed current loop? 



#2
Mar2306, 10:32 PM

HW Helper
PF Gold
P: 1,123

Qv = iL = j HW L . For a disk that's rotating, each dQ moves around a ring
with velocity v = omega x r. just add them up. 


Register to reply 
Related Discussions  
Magnetic dipole moment  Advanced Physics Homework  8  
magnetic dipole moment  Introductory Physics Homework  11  
Magnetic Dipole Moment  Classical Physics  2  
why is the electric dipole moment of an atom zero, but the magnetic moment nonzero?  Quantum Physics  9  
Magnetic dipole moment  Advanced Physics Homework  1 