Calculating Resistance of a Non-Metallic Pencil Lead | 390 Ohm Example

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Homework Help Overview

The discussion revolves around calculating the resistance of a non-metallic pencil lead, given its resistivity, length, and diameter. The original poster presents a specific example with expected resistance values.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster considers using the formula for resistance but questions the relevance of the material type and its implications on the calculation. Other participants discuss the validity of the resistivity units and the applicability of the resistance formula to non-metallic materials.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the problem and questioning the assumptions related to the material properties. Some guidance has been offered regarding the formula, but clarity on the material's impact on resistance remains a topic of discussion.

Contextual Notes

There is mention of potential confusion regarding the uniformity of materials used in resistors and how that might affect the application of the resistance formula. The original poster also expresses uncertainty about the relevance of the material type to the problem.

qim
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I have a question:

A pencil "lead" is made from non-metallic material which has a resistivity, at room temperature, of 4.0 x 10^-3 m.

A piece of this meterial has a length of 0.15 m and a diameter of 1.40 x 10^-3 m.

Show that the resitance of this specimen is 390 Ohm.

-----


Well I though of using R = rho x l / A

But then I read earlier that " by examining the dimensions of the resistor (assuming it is made from resistance wire instead of carbon as some are) we can also work out its resistance"

Does that mean that the question is a red herring, as the pencil lead is made from non metallic material?

Help...

Thanks

qim
 
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Other than the units being wrong for resistivity (they should be ohmsxlength, not just length) there is no "red-herring". It is just a simple multiplication.

Njorl
 
Thanks Njorl

But what am I to make of the statement that the equation should only work for resistors made of resistance wire?

That's the bit I could not understand.

Thanks

qim
 
I'm just guessing here:

Is it possible that they're covering themselves to take into account that typical resistors aren't uniform on the inside? IIRC, some are (deliberately) packed with small pockets of air.
 

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