How do you find the sum of the digits of number N? Say N = 10

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Discussion Overview

The discussion revolves around the method for finding the sum of the digits of a number N, with specific examples provided, including N = 10 and a much larger number. Participants explore different interpretations of the question and the implications of summing digits versus summing a series of integers.

Discussion Character

  • Exploratory, Debate/contested, Conceptual clarification

Main Points Raised

  • One participant asks how to find the sum of the digits of N, specifically using N = 10 as an example.
  • Another participant references the formula for the sum of the first N integers, suggesting it might relate to the question but acknowledges it requires proof by induction.
  • A participant clarifies that the sum of the digits of 10 is 1 + 0 = 1, indicating a potential misunderstanding of the original question.
  • One participant notes that the formula for the sum of integers only holds under certain conditions, such as when the digits form an arithmetic progression, and provides an example with N = 12245.
  • Another participant admits to having answered a different question than intended, expressing a light-hearted acknowledgment of the confusion.
  • A participant introduces a hypothetical scenario involving a much larger N, prompting further exploration of how to sum the digits in such a case.
  • Another participant humorously expands on the previous point, illustrating the sum of digits for a long number with a playful tone.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the interpretation of the original question, with multiple competing views on how to approach the sum of digits versus the sum of a series of integers.

Contextual Notes

Some assumptions about the nature of N and the definitions of summing digits versus summing integers remain unresolved, leading to varied interpretations of the question.

PrudensOptimus
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How do you find the sum of the digits of number N?


Say N = 10
 
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If memory serves me correctly:

[tex] \sum_{k=1}^N k= \frac{N(N+1)}2[/tex]

a fact that you would prove by induction.
 
Was that what was meant? The "sum of the digits" of 10 is 1+ 0= 1, of course.
 
Originally posted by BigRedDot
If memory serves me correctly:

[tex] \sum_{k=1}^N k= \frac{N(N+1)}2[/tex]

a fact that you would prove by induction.

It will be true only if the digits form a Arithmetic Projection
for eg N=2468 etc {2+4+6+8}
but not in general say for N=12245 {1+2+2+4+5}
 
The "sum of the digits"
You're right, I answered a completely different question. Well, I am sure someone asked my question somewhere, sometime. :)
 
Originally posted by HallsofIvy
Was that what was meant? The "sum of the digits" of 10 is 1+ 0= 1, of course.


Yea what if N = 1231247839783924723840723084732084738274... + ... N?
 
Originally posted by PrudensOptimus
Yea what if N = 1231247839783924723840723084732084738274... + ... N?

Ofcourse it would be
as N=1+0
here it will be N=1+2+3+1+2+4+7+8+3+9+7+8+3+9+2+4+7+2+3+8+4+0+7+2+3+0+8+4+7+3+2+0+8+4+7+3+8+2+7+4+...+x+y+z+a+b+c+d :wink: :wink: :wink:
 

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