Can someone helpme with this question

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SUMMARY

The discussion centers on the application of the Lorentz force equation, F = q(v x B), to a charged particle moving in a magnetic field. Participants explore the relationship between force and velocity, demonstrating that they are perpendicular and maintain constant magnitude. The hint provided suggests using the derivative of the dot product of velocity, v, with itself to establish these properties, specifically applying the product rule for differentiation.

PREREQUISITES
  • Understanding of the Lorentz force equation
  • Familiarity with vector calculus and dot products
  • Knowledge of Newton's second law of motion
  • Ability to apply the product rule in differentiation
NEXT STEPS
  • Study the derivation of the Lorentz force in electromagnetic theory
  • Learn about vector calculus, focusing on dot and cross products
  • Explore Newton's laws of motion in the context of charged particles
  • Investigate the implications of constant magnitude in particle motion
USEFUL FOR

Students and professionals in physics, particularly those studying electromagnetism and mechanics, as well as educators seeking to clarify concepts related to charged particle dynamics in magnetic fields.

jlmac2001
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The force acting on a moving charge particle with mass m and charge q in a magnetic field B is the Lorentz force F= q(v x B), where v is it's velocity. Suppose thata particle moves in the (x,y) plane with a uniform B field in the z direction. Assuming Newton' second law, mdv/dt = F, show that the forceand velocity are perpendicular, and that both have constan magnitude. Hint: Find (d/dt)(v dot v).


I don't know where to start. How do you take the derivative of v dot v?
 
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Use the product rule:

[tex] \frac{d}{dx}( f \cdot g ) = f \cdot \frac{dg}{dx} + \frac{df}{dx} \cdot g[/tex]
 
still don't get it

Can you elaborate? I don't understand.
 

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