## Find plane, given a line & perpendicular plane

Please help me! I have been sitting with this problem for god knows how long, and I just can't figure it out. I've tried re-reading the problem text, re-reading the chapter, reading alternative explanations on the web, drawing the problem on paper -- heck, I've even tried shouting at it -- but no luck. Can someone please give me some pointers?

The problem?
Find the equation of the plane that satisfies the given conditions:
Passing through the line x+y=2, y-z=3, and perpendicular to the plane 2x+3y+4z=5.

Firstly, I'm not even sure if I'm reading it correctly. Does passing through mean that the plane contains the line, or that it passes through a point in the line? Is it one line (x+y=2, y-z=3) or two lines (x+y=2 and y-z=3)?I haven't seen it in that form before. Is it the wanted plane or the line that is perpendicular to the given plane? Secondly, how do I solve it?

I have a feeling that this should be easy, so this is really bad for my self-confidence. :-(
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