| Thread Closed |
Euclidean rings |
Share Thread | Thread Tools |
| Nov21-06, 05:57 AM | #1 |
|
|
Euclidean rings
Let
[tex]\displaystyle{\zeta = e^{{2\pi i} \over 5}}[/tex] I need to show that [itex]Z[\zeta][/itex] is a Euclidean ring. The only useful technique I know about is showing that given an element [itex]\epsilon \in Q(\zeta)[/itex] we can always find [itex]\beta \in Z[\zeta][/itex] such that [itex]N(\epsilon - \beta) < 1[/itex] (using the standard norm for the euclidean function). This usually involves finding a general expression for the norm and then saying that you can choose beta such that the difference of each basis element is less than 1/2, and then showing that this means you can also get the norm less than 1. However, the expression I got for the norm here didn't seem to lend itself to this method. Any suggestions on how to do this? |
| Nov21-06, 06:10 PM | #2 |
|
Recognitions:
|
show it has a thingummmy - euclidean function, can't remember the precise name, that might help.
|
| Nov21-06, 11:55 PM | #3 |
|
|
Of course, but that's the point. The problem is I can't show the Norm is less than one if the coefficients are less than 1/2 and don't know any other techniques.
|
| Thread Closed |
| Thread Tools | |
Similar Threads for: Euclidean rings
|
||||
| Thread | Forum | Replies | ||
| Units and prime elements in euclidean rings | Linear & Abstract Algebra | 10 | ||
| Another Euclidean ring | Linear & Abstract Algebra | 9 | ||
| euclidean geometry | General Math | 3 | ||
| Euclidean and Non Euclidean Space? | Differential Geometry | 1 | ||
| Non-Euclidean triangle | General Math | 1 | ||