Solve Differential Equation: \ddot{\theta} = c \cos{\theta}

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Homework Help Overview

The discussion centers around solving the differential equation \(\ddot{\theta} = c \cos{\theta}\), which falls under the subject area of differential equations in physics.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants suggest numerical methods such as Runge-Kutta and discuss approximations for small angles. There is also a discussion about manipulating the equation by multiplying by \(2\dot{\theta}\) and recognizing a relationship involving \(\sin{\theta}\). Questions arise about the ease of integration and the specifics of solving the resulting integral.

Discussion Status

Participants are actively exploring various methods to approach the problem, including numerical solutions and analytical techniques. Some guidance has been provided regarding integration, but there is no explicit consensus on a single method or solution path.

Contextual Notes

There are references to specific constants and parameters, such as \(c\), \(g\), and \(L\), which may imply additional context or constraints that are not fully detailed in the discussion.

Logarythmic
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How do I solve

[tex]\ddot{\theta} = c \cos{\theta}[/tex]?
 
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Numerically. Try Runga Kutta, or for small angles Cos ( [itex]\theta[/itex]) ~ 1 so solve

[tex]\ddot{\theta} = c[/tex]
 
Logarythmic said:
How do I solve

[tex]\ddot{\theta} = c \cos{\theta}[/tex]?

Multiply by [itex]2\dot{\theta}[/itex] and then notice that you get

[tex]\frac{d}{dt}\dot{\theta}^{2} = c\frac{d}{dt}{\sin\theta}[/tex]

The rest is easy.

Daniel.
 
Is it? =P

[tex]\dot{\theta}^2 = c_1 \sin{\theta} + c_2[/tex]?
 
Yes, now separate variables and integrate.

Daniel.
 
"The rest is easy"!:smile:
 
Ok, so now I got the integral

[tex]\int \frac{d\theta}{\sqrt{c - \frac{3g}{L}sin{\theta}}}[/tex]

to solve. Any tip?
 

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