Understanding Charge and Current in a Series of Questions

  • Thread starter Thread starter Spectre32
  • Start date Start date
  • Tags Tags
    Test
Click For Summary

Homework Help Overview

The discussion revolves around two questions related to charge distribution and current in electrical circuits. The first question involves three identical metal spheres with varying initial charges and the process of charge equalization upon contact. The second question pertains to calculating the time it takes for a specific number of electrons to pass through a wire carrying a current.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the process of charge equalization between the spheres and the implications of charge conservation. Questions arise regarding the assumptions made about the duration of contact and the distribution of charge after separation. In the second question, there is confusion about the interpretation of the current and the calculation of time.

Discussion Status

Participants are actively engaging with the problems, exploring the concepts of charge distribution and current. Some guidance has been offered regarding the need for charge equilibrium and the steps involved in the calculations. There is a recognition of the need to clarify assumptions and the reasoning behind the calculations.

Contextual Notes

Participants note the importance of charge conservation in the first question and the potential misunderstanding regarding the calculation of time in the second question. There is an acknowledgment of the instructor's feedback and the need to revisit the calculations.

Spectre32
Messages
136
Reaction score
0
Ok I got two questions dealing with Charge and Current.

1) Consider three identical metal spheres . Initally , sphere A contains a charge of 2uC and B contains a charge of 10uC. Sphere C has a charge of -4uC. Spheres A and B touch each other, and then are separated. Then Sphere B and C touch and then separate. What is the charge on C now.

I had gusses positive and he marked .5 off soo i assume i need a number with that. Not sure what to do with it.

2)If a metal wires carries a current of 80.mA, how long does it take for the 3.00 x10^20 electrons to pass a given corss-sectional area of the wire.

I had use I= deltaQ/delta t and had gotten 2 seconds. his resposne was "correct, but now solve for delta t... i through i just sloved for it.



Thanks for the help.
 
Physics news on Phys.org
Originally posted by Spectre32
1) ...
I had gusses positive and he marked .5 off soo i assume i need a number with that. Not sure what to do with it.
It's just an accounting problem. You have to make the assumption (I'm assuming) that the contact between the spheres lasts long enough for the charge to reach equilibrium. Do it in two steps.




Originally posted by Spectre32
2) ...
his resposne was "correct, but now solve for delta t... i through i just sloved for it.
Ya, I agree with you. I can't imagine what he was thinking about. (I did not check to see if 2 s is correct.)
 
Last edited:
Alirhgt awosome, also so what you were saying in my first question. THe charges equalize and then you take that charge and add it to the negative one... correct.
 
Originally posted by Spectre32
THe charges equalize and then you take that charge and add it to the negative one... correct.
"that charge?" I don't know to what you are referring. A and B join together to share all of their charge. Since they are identical metal spheres (and since we are making previously said assumption), they will share the charge half and half. But don't forget that they separate, after which, you will have a new distribution of charge among the three spheres (not 2, 10, -4 any more). Then, according to this new distribution, you do step 2.

One way to check to see if you made a mistake is to add all the charges and see if it is the same as what you would get if you add all the charges in the original distribution. You can use this to check each step, because charge is conserved.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 21 ·
Replies
21
Views
6K
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
6K