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Reflection grating

by VVill
Tags: grating, reflection
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VVill
#1
Jan25-07, 05:11 PM
P: 3
1. The problem statement, all variables and given/known data



2. Relevant equations
d=1/N d*sin(theta)=m*(lambda)


3. The attempt at a solution
d=1/1970
d=.0005076

.0005076*sin(theta)=2*600e-9

sin(theta)=.0000012/.0005076

arcsin(.002364)=.135

*sigh*
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
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hage567
#2
Jan25-07, 05:47 PM
HW Helper
P: 1,542
One thing I see is that when you found d you didn't convert from cm to m, so you have inconsistent units in your equation.
VVill
#3
Jan26-07, 09:58 AM
P: 3
d=.0005076cm = .000005076m

.000005076*sin(theta)=2*600e-9

sin(theta)=.0000012/.000005076

arcsin(.2364)=13.7

Anything else I'm missing, because the answer is not 13.7?

hage567
#4
Jan26-07, 10:15 AM
HW Helper
P: 1,542
Reflection grating

Why do you have m=2? If it is first order I would think it would be m=1.
hage567
#5
Jan26-07, 11:37 AM
HW Helper
P: 1,542
Are you sure you are using the right equation? I think the grating equation you are using is not quite right for the conditions of your problem. The one you are using is a special case where the angle of incidence is normal to the grating. You need to include the angle of incidence in your equation. So your equation would be
d*(sin(theta(m)) - sin(theta(inc))) =m*lamda. where m = 1 for first order maxima. Anyway see if that helps.


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