
#1
Jan2507, 05:11 PM


#2
Jan2507, 05:47 PM

HW Helper
P: 1,542

One thing I see is that when you found d you didn't convert from cm to m, so you have inconsistent units in your equation.




#3
Jan2607, 09:58 AM

P: 3

d=.0005076cm = .000005076m
.000005076*sin(theta)=2*600e9 sin(theta)=.0000012/.000005076 arcsin(.2364)=13.7º Anything else I'm missing, because the answer is not 13.7º? 



#4
Jan2607, 10:15 AM

HW Helper
P: 1,542

reflection grating
Why do you have m=2? If it is first order I would think it would be m=1.




#5
Jan2607, 11:37 AM

HW Helper
P: 1,542

Are you sure you are using the right equation? I think the grating equation you are using is not quite right for the conditions of your problem. The one you are using is a special case where the angle of incidence is normal to the grating. You need to include the angle of incidence in your equation. So your equation would be
d*(sin(theta(m))  sin(theta(inc))) =m*lamda. where m = ±1 for first order maxima. Anyway see if that helps. 


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