# Using Integration by Parts

by LiveToDream
Tags: integration, parts
 P: 54 Are you sure it wasn't $$\sqrt {1-e^{-2x}}$$ instead of $$\sqrt {1-e(-2x)}$$, since that is a very strange way of writing it. If so, just remember that $$\frac {1}{e^{x}} = e^{-x} = \sqrt {e^{-2x}}$$ and set $$u = e^{-2x}$$
 P: 4 It was supposed to be 1/ $$\sqrt {1-e^{-2x}}$$ **How did you get that equation to show up that way? I just copy and pasted what you had to make it work this time and was curious how i would go about doing that.
 P: 54 Using Integration by Parts There is a \frac command in LaTex. To use it just type \frac {numerator}{denominator} So your problem would show up as: $$\int {\frac{dx}{e^{x}\sqrt{1-e^{-2x}}}$$ **Also check out this guide to LaTex typesetting http://www.physicsforums.com/misc/howtolatex.pdf