States of an atom in spectral notation

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Homework Help Overview

The discussion revolves around determining the possible states of an atom with a closed core plus one d electron, specifically in spectral notation. Participants are exploring the quantum numbers associated with angular momentum and their implications for the states of the atom.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of total angular momentum quantum number (J) based on the orbital angular momentum quantum number (L) and spin angular momentum quantum number (S). There is an exploration of the possible values of J and the relationship between L and S.

Discussion Status

Some participants have identified potential errors in the calculation of J values and are questioning the assumptions regarding the multiplicity of states. There is an ongoing examination of the rules governing the calculation of J, with some guidance provided on the correct interpretation of the quantum numbers.

Contextual Notes

Participants are addressing discrepancies between their calculations and the answers provided in reference materials. The discussion includes considerations of the total number of states based on the values of L and S, as well as the implications for the possible values of J.

Amith2006
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Homework Statement



1)Give in spectral notation the possible states of an atom which has a closed core plus one d electron.


Homework Equations





The Attempt at a Solution



I solved in the following way:
For d electron,
Orbital angular momentum quantum number(L)=2
Spin angular momentum quantum number(S)=1/2
Possible values of total angular momentum quantum number(J)= L+S,| L+S-1|,…,|L+S|
Hence,
J= (2+1/2), |2+1/2-1|,|2-1/2|
J= 5/2,3/2,1/2
Possible states of the atom in spectral notation are,
2 D 5/2, 2 D 3/2, 2 D ½
But the answer given in my book is 2 D 5/2, 2 D 3/2.
 
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Amith2006 said:

Homework Statement



1)Give in spectral notation the possible states of an atom which has a closed core plus one d electron.


Homework Equations





The Attempt at a Solution



I solved in the following way:
For d electron,
Orbital angular momentum quantum number(L)=2
Spin angular momentum quantum number(S)=1/2
Possible values of total angular momentum quantum number(J)= L+S,| L+S-1|,…,|L+S|
Hence,
J= (2+1/2), |2+1/2-1|,|2-1/2|
J= 5/2,3/2,1/2
thisis where your mistake is...

(2+1/2) = 5/2

|2+1/2-1| = 3/2

|2-1/2| = 3/2
 
nrqed said:
thisis where your mistake is...

(2+1/2) = 5/2

|2+1/2-1| = 3/2

|2-1/2| = 3/2

Sorry,I meant J=|L+S-2| =|2+1/2-2|=1/2 instead of J=|L+S-1|=3/2
Is there something to do with the multiplicity of states given by 2S+1 = 2 so that for a given value of J there are only 2 possible values L+S and L-S?
 
Last edited:
Amith2006 said:
Sorry,I meant J=|L+S-2| =|2+1/2-2|=1/2 instead of J=|L+S-1|=3/2
Is there something to do with the multiplicity of states given by 2S+1 = 2 so that for a given value of J there are only 2 possible values L+S and L-S?

I think you misunderstand the rule. You calculate L+S and then you calculate |L-S|. J may take any value between those two extremes, differing by steps of one.

In your example, L+S = 5/2 and |L-S| = |2-1/2| = 3/2.

So the possible values of J are 3/2 and 5/2. J=1/2 is not possible.

Of course, you can check that the number of states comes out right. L=2 has 5 states and S=1/2 has two states so the total number of states is 10.

Now, J=5/2 has 6 states and J=3/2 has 4 states so the total number checks out.
 
Thats cool!Thanx.
 

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