Integration sines and cosines question

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The forum discussion centers on integrating the product of sine and cosine functions, specifically demonstrating that the integral from -π to π of sin(3x)cos(4x)dx equals zero. Users suggest expressing sine and cosine in exponential form using the correct formulas: sin(x) = (e^(ix) - e^(-ix))/(2i) and cos(x) = (e^(ix) + e^(-ix))/2. The integration approach involves applying these exponential forms and utilizing trigonometric reduction formulas to simplify the expression accurately.

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ilikephysics
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Express the sines and cosines in exponential form and integrate to show that (integral from -pi to pi) sin(3x)cos(4x)dx=0

What I'm thinking is that I should use sin x=e^x-e^-x/2 and cos x=e^x+e^-x/2. And I should multiply sin times 3 and cos times 4 and integrate. And get something like this:

(e^3pi+e^-3pi/2 * e^4pi-e^-4pi/2) - (e^-3pi+e^3pi/2 * e^-4pi-e^4pi/2)=0

I don't think this is right though. Can someone help please?
 
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Try looking up and using some trig reduction formulas.

cookiemonster
 
Yes, I would be inclined to use "reduction formulas" but if the problem specifically said "Express the sines and cosines in exponential form", then the way ilikephysics is approaching this is correct.

However, the formulas are wrong!

[tex]sin(x)= \frac{e^{ix}-e^{-ix}}{2i}[/tex]
[tex]cos(x)= \frac{e^{ix}+e^{-ix}}{2}[/tex]

ilikephysics forgot the "i"s.
 

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