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Torque/Static Equilibrium/Forces problem.... |
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| Apr29-07, 04:49 PM | #1 |
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Torque/Static Equilibrium/Forces problem....
I have been working on this problem for a few hours, but I just can't get it ...
1. The problem statement, all variables and given/known data Problem: A 3.0-m-long rigid beam with a mass of 100 kg is supported at each end. An 80 kg student stands 2.0 m from support 1. How much upward force does support 1 exert on the beam? here is an image: http://photo.ringo.com/208/208651783O865465193.jpg ---- 2. Relevant equations τ=Frsinφ F=ma 3. The attempt at a solution I figured out the torques kinda, but do i use the mass as (2/3*100)+80? or (2/3*100)+40...either way i kept getting a wrong answer.... and the center of mass i assume is where the person is right? bec the 80kg addition would be the most massive point right? since the angles are 90 degrees, the sine of φ doesnt matter right?, i mean it would only affect the sign +/- of the answer....since τ=Frsinφ, and φ is either 90 or -90 degrees... idk...basically i just cant get this... i got solutions ranging from 76.666.., 1306.666... etc... |
| Apr29-07, 04:54 PM | #2 |
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Recognitions:
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Assume the weight of the beam acting at the center of the beam, and set the sum of all torques with respect to support B equal zero.
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| Apr29-07, 05:02 PM | #3 |
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| Apr29-07, 05:41 PM | #4 |
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Recognitions:
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Torque/Static Equilibrium/Forces problem.... |
| May1-07, 04:28 PM | #5 |
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lol...yea i got it, thanks, i went to a tutor today bec i was making small errors...i for the torque of the person, i was using the weight as (person+segment of rod), when its only supposed to be person
thanks for the help, greatly appreciated |
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