## Challenging Question

This question is one i got from uni. i just cant seem to get the right answers. Please post your worked solutions, i will tell you if you get the answer found on my sheet. Best of luck Guys, you might need it.

A 3.00 kg block of wood is suspended at rest by a thin thread attached to a supporting beam. A bullet of mass 32.0 g is fired vertica1ly upwards with velocity 415 m/s into the wood directly above it. The block and the bullet inside it move upwards together.

1 Determine the speed of the upward moving block and bullet immediately after the collision.
.
2 Calculate the total kinetic energy of the block and bullet immediately after the collision.

3 Calculate the maximum height the block and bullet reach.
 Mentor Blog Entries: 1 Sounds like a straightforward homework problem to me! Why don't you show what you've done so far?
 Blog Entries: 1 Recognitions: Gold Member Science Advisor Staff Emeritus Welcome to the Forums Willtd, According to our forum guidelines, one is expected to show one's own efforts before asking for help. So if you post your attempted solution, we might be able to show you where've you've gone wrong. In addition, we have dedicated Homework & Coursework forums for such questions. Edit: The Doc Strikes again.

Blog Entries: 9
Recognitions:
Homework Help

## Challenging Question

Do you think you are some kind of a professor? hehe

Please obey the guidelines of these forums.
 I got it!! Here is a solution for anybody who wants it. :) 1. m1v1 = m2v2 .032x415 = 3.032v v = 4.379 2. Total Ke = 0.5 x m x v^2 = 0.5x 3.032x4.38^2 = 29.1 3. v^2 = u^2 +2as v (final speed) = 0 s = sqrt [(4.38^2) / (2x9.8)] = 0.98m
 Blog Entries: 9 Recognitions: Homework Help Science Advisor hehe.. are you joking with us? :)

 Quote by malawi_glenn hehe.. are you joking with us? :)
Maybe you should help next time m8 :D

Blog Entries: 9
Recognitions:
Homework Help