Simple marginal distribution problem

Hey guys,

Doin revision for my maths exam and i came across this question from a past exam:

1. The problem statement, all variables and given/known data
Find fx(x,y) of
$$f(x,y) = \frac{(1+4xy)}{2} for 0 \leq x, y \leq 1$$ and zero otherwise

2. Relevant equations
Now this should equal$$\int \frac{(1+4xy)}{2} dy$$over all y but that leads to infinities ( as y goes from minus infinity to 1)which obviously we can't have. Im sure im missing something simple and stupid i just need someone to point ito out :)

Cheers
-G

NOTE: Sorry this latex is stuffing up, tryin to fix it
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 Recognitions: Homework Help Science Advisor You might want to split the integral into a couple of pieces. Remeber: $$f(x,y) \neq \frac{1+4xy}{2}$$
 I think what Nate is trying to say is that f(x,y) is only defined on a certain domain. Since f(x,y) is a pdf, y cannot be arbitrarily negative as this would make f(x,y) negative. Remember, the integral of f(x,y) over the domain must be 1. Try to make sense of your domains. Draw them. X and Y can sometimes be dependant on each other...which can make things complicated.

Recognitions:
Homework Help

Simple marginal distribution problem

Doesn't this expression,

$$0 \leq x, y \leq 1$$

mean x and y are both in [0,1]? If y runs to minus infinity the question doesn't make much sense.

Recognitions:
Homework Help
Actually, $f(x,y)$ is only non-zero on a certain domain, it's defined on the entire plane.
 Quote by NateTG Actually, $f(x,y)$ is only non-zero on a certain domain, it's defined on the entire plane.