Calculating Distance Moved by Boat with a Boy Aboard

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The discussion centers on calculating the distance a boat moves when a boy shifts his position from the stern to the bow. Given the mass of the boat (M=80kg) and the boy (m=36kg), the principle of conservation of momentum is applied, leading to the equation M_{boat} \Delta {X_{boat}} + m_{boy}\Delta {X_{boy}} = 0. By establishing a reference frame at the bow of the boat, the displacement of the boat can be calculated using the relationship between the boy's displacement and the boat's length (2.8m).

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The mass of a boat is M=80kg, the mass of a boy is m=36kg. The boy moves from the stern to the bows of the boat. What distance does the boat move, if its length is 2.8m? At such low speeds the water resistance may be neglected. Hint: Center of mass remains at rest.

Please help because I am stumped... :confused:
 
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[tex]M_{boat} \Delta {X_{boat}} + m_{boy}\Delta {X_{boy}} =0[/tex]

Coose ur reference frame let it be at the bow of the boat
Now dboy=dboy/boat+dboat

Let x be the displacement of boat then (Delta)Xboat = x
then
dboy = x-l

Where l is the length
 

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