Gravitation Problem (stuck on Algebra )

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SUMMARY

The discussion centers on solving a gravitation problem involving the balance of gravitational forces between the Earth and the Sun on a space probe. The key equations derived include the law of universal gravitation, expressed as G * (Ms * m) / r1^2 = G * (Me * m) / (d - r1)^2, where Me is the mass of Earth, Ms is the mass of the Sun, m is the mass of the probe, r1 is the distance from the Earth to the probe, and d is the total distance from the Earth to the Sun. The solution involves algebraic manipulation to isolate r1, ultimately leading to the formula r1 = d * sqrt(Me / (Ms + Me)).

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  • Basic algebraic manipulation skills
  • Familiarity with gravitational constants and mass units
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Gravitation Problem (stuck on Algebra!)

We just started Gravitation in my Physics class. Here is the problem:
How far from Earth must a space probe be along a line toward the Sun so that the Sun's gravitational pull on the probe balances Earth's pull?

Sorry I'm really bad with the Latex programming and it will take forever to do so here are my calculations. The first part is naming the variables.
Me = Mass of Earth
Ms = Mass of Sun
m = mass of space probe
r1 = dist. from center of Earth to probe
r2 = dist. from center of the Sun to probe

[tex]\frac {GMem}{r1^2}[/tex] = [tex]\frac {GMsm}{r2^2}[/tex]


First I substituted r2 = d-r1 , where d is the distance from center of Earth to sun.


[tex]\frac {Me}{r1^2}[/tex] = [tex]\frac {Ms}{(d-r1)^2}[/tex]

Ok, here's the Algebra part that I can't figure out...

Sorry , I have no idea how to write this in Latex!

r1 = d squareroot of Me / squareroot of Ms + Me

I don't know how to get to that, what is the Algebra. Or a simple analogy for me to understand it? Thanks. ~David Wilkerson
 
Last edited:
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You almost finished it yourself... :smile:

[tex]G\frac{M_em}{r_1^2} = G\frac{M_sm}{r_2^2}[/tex]
Becomes:
[tex]\frac{M_e}{r_1^2} = \frac{M_s}{r_2^2}[/tex]

The other equation is:
[tex]d = r_1 + r_2[/tex]
As you said. Two equations, two unknowns, you can solve it. :smile:

[tex]\frac{M_e}{r_1^2} = \frac{M_s}{(d - r_1)^2}[/tex]
 


Hi David,

Don't worry, I understand that algebra can be tricky sometimes. Let's break down the problem step by step.

First, we need to understand what the problem is asking us to do. We need to find the distance, r1, from the center of Earth to the space probe, where the gravitational pull of the Sun and Earth on the probe is balanced. In other words, the probe is not being pulled more towards one object than the other.

Next, we need to set up an equation that represents this situation. In physics, we use the law of universal gravitation, which states that the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This can be written as:

F = G * (m1 * m2) / r^2

Where F is the force of gravity, G is the universal gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

Now, let's apply this equation to our problem. We have three objects: the Sun (m1 = Ms), the Earth (m2 = Me), and the space probe (m3 = m). We also know that the force of gravity between the Sun and the probe is equal to the force of gravity between the Earth and the probe. Therefore, we can set up an equation like this:

G * (Ms * m) / r1^2 = G * (Me * m) / (d - r1)^2

Where r1 is the distance between Earth and the probe, and d is the distance between the Sun and the probe.

Next, we can simplify this equation by dividing both sides by G and multiplying both sides by (d - r1)^2. This will cancel out the G and we will be left with:

(Ms * m) / r1^2 = (Me * m) / (d - r1)^2

Now, we can cross multiply and solve for r1:

(Ms * m) * (d - r1)^2 = (Me * m) * r1^2

Expand the brackets:

(d^2 - 2dr1 + r1^2) * Ms * m = Me * m * r1^2

Multiply out the terms:

d^2Ms + (-2dr1 * Ms) + (r1^
 

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