Solve Diffraction Problem: Find Slit Width

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Homework Help Overview

The discussion revolves around a single slit diffraction problem, where participants are tasked with finding the width of the slit based on given measurements of the diffraction pattern and the wavelength of light.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the geometry involved in determining the angle related to the first minimum of the diffraction pattern. There are attempts to relate the angle to the slit width using the wavelength of light. One participant seeks further clarification on the concepts presented.

Discussion Status

The discussion is ongoing, with some participants providing geometric insights and relationships between the variables involved. There is an indication of productive dialogue, as one participant requests additional explanation to enhance understanding.

Contextual Notes

Participants are working with specific measurements and relationships defined by the principles of diffraction, but there may be gaps in understanding the underlying geometry and calculations involved.

percy_07
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Diffraction...need help bad

Suppose that a single slit diffraction pattern is displayed on a screen. The distance between the first minimum on the left of the screen and the first minimum on the right is 5.4mm. The screen is 0.9m from the slit and the wavlength of light is 546nm. Calculate the width of the slit??
 
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Simple case of considering the geometry of the situation. The first minimum will occur as ligh has interfered destructively at the first minimum [tex]\Theta_1[/tex]

thus [tex]sin \Theta_1=\frac{\lambda} {b}[/tex]

Where b is the slit width
 
Last edited:
Ok to find theta is a simple case of geometry. Construct a triangle from the slit to the screen and use the values given to determine the angle of the ray. Once calculated you have lambda so the only thing you don't know is b, which will be the sine of theta divided by lambda.
 
could you explain it a little more for me please I am still not grasping it 100%.
 

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