|Sep12-07, 06:52 AM||#1|
Torque calculation, is this correct?
I'm experimenting some ideas and needed a verification of my formula.
There is a torque arm of 15" with a force of 6000 lbs perpendicular to the axis of rotation. So that calculates to 7500 ft/lbs (6000*15/12). So on the same axis, there is a torque arm of 5" the must oppose this force equally, I need that force required. I calculated 18000 lbs of opposing force with 7500 ft/lbs at the axis (7500/5*12).
Is this valid?
No its not a homework question :) I need to know how powerful a single disc brake on a truck is.
Thanks in advance.
|Sep12-07, 07:04 AM||#2|
Yes. If you have 1/3 of the moment arm, you need 3 times the force to give the same torque.
|Sep12-07, 07:06 AM||#3|
|Similar Threads for: Torque calculation, is this correct?|
|Is this Gaussian Integral calculation correct?||General Physics||3|
|[SOLVED] Torque Calculation||Mechanical Engineering||4|
|ochem energy calculation - correct answer?||Chemistry||1|
|Torque Calculation||General Physics||2|