
#1
Sep1507, 03:36 PM

P: 46

1. The problem statement, all variables and given/known data
Progressive waves are generated on a rope by vibrating vertically the end, P, in simple harmonic motion of amplitude 90 mm. The wavelength of the waves is 1.2 m and they travel along the rope at a speed of 3.6ms–1. Assume that the wave motion is not damped. Calculate the maximum speed of point P. 3. The attempt at a solution The actual solution is V=2(pi)xfxA Since f=v/wavelength= 3.0 Hz and A=90x10^3m the answer is 1.70 m/s I don't understand why this formula is used and where the 2pi has come from. Is it to do with simple harmonic motion? I would be very grateful if someone could help with a derivation of the formula. 



#2
Sep1507, 03:51 PM

HW Helper
P: 4,125

What is the general equation of a wave?




#3
Sep1507, 03:56 PM

P: 46





#4
Sep1507, 04:11 PM

HW Helper
P: 4,125

Max. speed of particle on wavex = Acos(kx  wt) 



#5
Sep1507, 04:20 PM

P: 46

oh gosh no I haven't! erm on my physics data sheet there's a similar equation: x=Acos2Pift. hmmm I'll see what comes up when I google the equation you just gave me! Thanks



Register to reply 
Related Discussions  
What kind of wave is associated with particles , in wave particle duality?  Quantum Physics  7  
How does the V shape of a shock wave depend on the speed of the wave source?  Introductory Physics Homework  1  
particle wave conception of wave function  General Physics  0 