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[SOLVED] finding distance based off acceleration |
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| Oct6-07, 03:36 PM | #1 |
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[SOLVED] finding distance based off acceleration
1. The problem statement, all variables and given/known data
A car slows down uniformly from a speed of 26.0 m/s to rest in 4.50 s. How far did it travel in that time? 2. Relevant equations Acceleration (you all know it) 3. The attempt at a solution I am totally stuck all I can do is find acceleration ...-5.78m/s^2 |
| Oct6-07, 03:43 PM | #2 |
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What kinematics formulas do you know for uniform acceleration? displacement formulas...
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| Oct6-07, 03:43 PM | #3 |
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If you've found the acceleration, is there any other equation you know where you can work out the distance?
http://www.physicsforums.com/showpos...63&postcount=2 |
| Oct6-07, 03:50 PM | #4 |
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[SOLVED] finding distance based off acceleration
[tex]x = x_0 + v_0 t + (1/2) a t^2[/tex] Should I try using this?
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| Oct6-07, 03:55 PM | #5 |
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you can also use [tex]d = \frac{(v1 + v2)}{2}*t[/tex] which also gives you the answer. |
| Oct6-07, 03:58 PM | #6 |
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45.495m is that right?
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| Oct6-07, 03:59 PM | #7 |
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| Oct6-07, 04:06 PM | #8 |
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I accidentally pluged accel. in for velocity
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| Oct6-07, 04:06 PM | #9 |
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so.. 26*4.5-1/2(-5.78) what am I missing
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| Oct6-07, 04:18 PM | #10 |
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58.5?....v1 26m/s v2 0m/s t=4.5
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| Oct6-07, 04:18 PM | #11 |
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You should add on the acceleraton term and multiply it by the time squared.
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| Oct6-07, 04:19 PM | #12 |
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| Oct6-07, 04:20 PM | #13 |
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I totally was making that harder than it was, I would like to thank you for your help
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