[SOLVED] finding distance based off acceleration

1. The problem statement, all variables and given/known data

A car slows down uniformly from a speed of 26.0 m/s to rest in 4.50 s. How far did it travel in that time?

2. Relevant equations
Acceleration (you all know it)

3. The attempt at a solution
I am totally stuck all I can do is find acceleration ...-5.78m/s^2
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 Recognitions: Homework Help What kinematics formulas do you know for uniform acceleration? displacement formulas...
 Recognitions: Gold Member Science Advisor Staff Emeritus If you've found the acceleration, is there any other equation you know where you can work out the distance? http://www.physicsforums.com/showpos...63&postcount=2

[SOLVED] finding distance based off acceleration

$$x = x_0 + v_0 t + (1/2) a t^2$$ Should I try using this?

Recognitions:
Homework Help
 Quote by JDR 007 $$x = x_0 + v_0 t + (1/2) a t^2$$ Should I try using this?
you can do that since you've calculated acceleration.

you can also use $$d = \frac{(v1 + v2)}{2}*t$$

which also gives you the answer.
 45.495m is that right?

Recognitions:
Homework Help
 Quote by JDR 007 45.495m is that right?
No. how did you get that?
 I accidentally pluged accel. in for velocity
 so.. 26*4.5-1/2(-5.78) what am I missing
 58.5?....v1 26m/s v2 0m/s t=4.5
 Recognitions: Gold Member Science Advisor Staff Emeritus You should add on the acceleraton term and multiply it by the time squared.

Recognitions:
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Science Advisor
Staff Emeritus
 Quote by JDR 007 58.5?....v1 26m/s v2 0m/s t=4.5
That is correct.
 I totally was making that harder than it was, I would like to thank you for your help
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