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[SOLVED] finding distance based off acceleration

 
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Oct6-07, 03:36 PM   #1
 

[SOLVED] finding distance based off acceleration


1. The problem statement, all variables and given/known data

A car slows down uniformly from a speed of 26.0 m/s to rest in 4.50 s. How far did it travel in that time?

2. Relevant equations
Acceleration (you all know it)


3. The attempt at a solution
I am totally stuck all I can do is find acceleration ...-5.78m/s^2
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Oct6-07, 03:43 PM   #2
 
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What kinematics formulas do you know for uniform acceleration? displacement formulas...
Oct6-07, 03:43 PM   #3
 
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If you've found the acceleration, is there any other equation you know where you can work out the distance?

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Oct6-07, 03:50 PM   #4
 

[SOLVED] finding distance based off acceleration


[tex]x = x_0 + v_0 t + (1/2) a t^2[/tex] Should I try using this?
Oct6-07, 03:55 PM   #5
 
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Quote by JDR 007 View Post
[tex]x = x_0 + v_0 t + (1/2) a t^2[/tex] Should I try using this?
you can do that since you've calculated acceleration.

you can also use [tex]d = \frac{(v1 + v2)}{2}*t[/tex]

which also gives you the answer.
Oct6-07, 03:58 PM   #6
 
45.495m is that right?
Oct6-07, 03:59 PM   #7
 
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Quote by JDR 007 View Post
45.495m is that right?
No. how did you get that?
Oct6-07, 04:06 PM   #8
 
I accidentally pluged accel. in for velocity
Oct6-07, 04:06 PM   #9
 
so.. 26*4.5-1/2(-5.78) what am I missing
Oct6-07, 04:18 PM   #10
 
58.5?....v1 26m/s v2 0m/s t=4.5
Oct6-07, 04:18 PM   #11
 
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You should add on the acceleraton term and multiply it by the time squared.
Oct6-07, 04:19 PM   #12
 
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Quote by JDR 007 View Post
58.5?....v1 26m/s v2 0m/s t=4.5
That is correct.
Oct6-07, 04:20 PM   #13
 
I totally was making that harder than it was, I would like to thank you for your help
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