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simplifying equation

 
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Oct17-07, 11:06 PM   #1
 

simplifying equation


I am trying to solve for the variable lambda in terms of A. After multiplying the denominator term over to the other side, how do I go on from there? I don't know how to get rid of the exponential terms.

Thanks on advance.

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Oct17-07, 11:09 PM   #2
 
You can take the log of both sides
Oct18-07, 12:53 AM   #3
 
Or, you can use logical reasoning to conclude that if the bases on each side are equal, then...?
Oct18-07, 05:52 AM   #4
 
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simplifying equation


"the bases on each side are equal" and exponential is a one-to-one function!
Oct18-07, 07:12 AM   #5
 
After cancelling the ln's I end up with the equation below, but then it seems the lambdas cancel each other out. Is that correct? apparently from the solutions, lambda does not cancel.
Oct18-07, 07:33 AM   #6
 
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Quote by ACLerok View Post
After cancelling the ln's I end up with the equation below, but then it seems the lambdas cancel each other out. Is that correct? apparently from the solutions, lambda does not cancel.
You're equation looks correct so far, but you can reduce it to lamba in terms of A.

Hint: Expand the binomial on the RHS.
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