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[SOLVED] Gauss' Law With an Infinite Cylinder of Charge |
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| Oct27-07, 03:40 PM | #1 |
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[SOLVED] Gauss' Law With an Infinite Cylinder of Charge
1. The problem statement, all variables and given/known data
The test question was to find the potential difference between a point S above a cylinder of charger per length lambda, and a point on the surface of the cylinder having radius R and infinite length. 2. Relevant equations Stupid me tried to grind through it during the test. But looking at the prof's solution: http://www.phys.washington.edu/users...7exam1soln.pdf Here's the test if you need to know the question how he worded it: http://www.phys.washington.edu/users...21-07exam1.pdf Problem #1. I don't get how he got "E(s)*2pi*L*S I get the 2pi and L come from integrating over phi and the length of the cylinder, but I can't figure out where that S came from. Is it because you'd need a cosine(theta) for the direction that the cylinder is from S? Where cosine is S/distance? Then wouldn't he have to add in a bunch of other stuff? I'm just not seeing something here and I feel embarrassed. |
| Oct27-07, 04:27 PM | #2 |
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[tex]\int E \cdot dA = EAcos(\Theta)[/tex]
Where [tex]\Theta[/tex] is the angle between the surface of the cylinder and the electric field. Now, simplify this last expression. What is A? What is [tex]\Theta[/tex]? |
| Oct27-07, 04:46 PM | #3 |
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Ohhhhhh I get it. A is 2pi*Length*radius, and he's just using S as the radius, since it shouldn't matter.
Gotcha, thanks a bunch. |
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