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Orbital Energy of a binary star system |
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| Nov7-07, 06:17 PM | #1 |
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Orbital Energy of a binary star system
1. The problem statement, all variables and given/known data
Say you have a binary star sytem. Both stars have mass M and semimajor axis a. The orbits are extremely eccentric (e is approximately 1). How would you describe the energy of the system? 2. Relevant equations SEE BELOW 3. The attempt at a solution Basically I'm very unconfident about my answer and feel like I'm blanking on basic physics. I imagined the stars both at apocenter at some initial time. With such an eccentric orbit the velocities would be nearly zero here, so the total energy of each stars orbit would be quite nearly all potential energy. -Gmm/r where r is distance to the barycenter or 2a so the potential energy of each star is -(Gm^2)/2a. So the sum of the PE's would be 2 times this amount and therefore the total energy of the orbit is -(Gm^2)/a Is this valid? |
| Nov7-07, 07:38 PM | #2 |
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Essentially zero velocity at apastron would be a very special case.
This might be of use - http://instruct1.cit.cornell.edu/cou...ary/binary.htm http://www.astro.cornell.edu/academi...bin_orbits.htm http://filer.case.edu/sjr16/advanced/stars_binvar.html See this page - http://csep10.phys.utk.edu/astr162/l...es/visual.html - which also has an applet. Should the two stars have the same initial angular momentum? I was trying to think of a way to generalize circular binary orbits - e.g. http://hyperphysics.phy-astr.gsu.edu/hbase/orbv.html#bo |
| Nov7-07, 08:06 PM | #3 |
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| Nov7-07, 08:17 PM | #4 |
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Orbital Energy of a binary star system
If the kinetic energy was negligible, then at apastron, the total energy (neglecting the rotational energies of the stars) would simply be the gravitational potential energy at that distance/separation.
The java applets show that e=1 is extremely eccentric with little overlap of the orbits. But I was wondering about a more general case. I think one is assuming not only the same mass, but same eccentricity and angular momentum, i.e. the same (or symmetric) orbital parameters for both stars. |
| Nov7-07, 09:23 PM | #5 |
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| Nov7-07, 09:57 PM | #6 |
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Orbital mechanics in not my specialty, and it's been a long time since I've sat down and worked through such material. |
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