## Non-Inverting Operational Amplifier.

Good evening.

Right. My question is one of a simple nature, I think.

Anyways, consider the following non-inverting Op-Amp design:

http://www.freewebs.com/mushg/FWThumbnails/OpAmp.bmp

Now, the basic formula for any non-inverting opamp is of course $\frac{V_{O}}{V_{S}} = 1 + \frac{R_{2}}{R_{1}}$

Meaning that $V_{O} = V_{S} + \frac{V_{S}R_{2}}{R_{1}}$

I'm trying to find $V_{O}$

My question, how do I take into account the$R_{S}$ In this situation? Does it have any bearing at all, if so, what?

Thanks
 PhysOrg.com science news on PhysOrg.com >> King Richard III found in 'untidy lozenge-shaped grave'>> Google Drive sports new view and scan enhancements>> Researcher admits mistakes in stem cell study
 Recognitions: Gold Member Science Advisor Well, since the inputs are very high impedance, there's no current into them. Hence the R_s has no effect on the gain.
 Hi, Rs= 1.2k has nbo bearing at all. You cannot simply memorize the formulae for inverting and noninverting amps and solve every opamp question. You need to do it fron first principles. Heres how. 1. V+= V- (thats a given) 2. I= = I-= 0A (very little or no current in the order of pico amps enters intoi the terminals of the opamp ...it can be neglected) 3. You have an expression for V- being V-= Vout(5k)/(15K) by voltage divider and you have V+= 2A (no V drop across Rs as I+= 0A) << final solution deleted by berkeman >>

Blog Entries: 2
Recognitions:
Homework Help