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I don't know how to calculate a tennis racquet head size...thanks! 
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#1
Dec607, 05:58 AM

P: 7

Hi everybody,
The area of a tennis racquet head size is like an egg shape, not oval shape. how to calculate it? Thank you so much for your help ^_^ 


#2
Dec607, 06:11 AM

Math
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Thanks
PF Gold
P: 39,683

Unfortunately there are just too many different shapes for an "egg shape" for there to be any good formula. I think you will have to approximate the area by treating it as if the tennis racquet head were an oval or an "ellipse" for which there is an area formula: [itex]A= \pi ab[/itex] where a and b are half the distance across the racquet head measured where it is narrowest and widest.
In other words, you are really using the formula for area of a circle, but, because an "ellipse" does not have a single "radius", instead of r^{2}, you multiply together the values for smallest "radius" and largest "radius". 


#3
Dec607, 06:28 AM

P: 7

Thank you, HallsofIvy ^_^
The headsize of my racquet is 89.5 square inch that someone said but the brand said 93. Using W x L x 0.8 is closer to this area. I should use 22/7 x a x b or W x L x 0.8 to caculate the racquet headsize? http://www.tenniswarehouse.com/view...html?PCODE=LMP I'd like to calculate it by myself. Thanks! 


#4
Dec607, 06:34 AM

P: 61

I don't know how to calculate a tennis racquet head size...thanks!
Another idea to do might to be use Integration (just plot half the racquet onto the aces, find the area under the curve, then multiply by 2), though I'm not sure if you have done that before, but either way, it probably will be more accurate. 


#5
Dec607, 06:47 AM

P: 7

Almost forget to add: My racquet stringbed (hoop not included) length:12.25 inch, width 9 inch Could you please help me calculate it from the link I posted? Thank you ^_^ 


#6
Dec607, 08:25 AM

Sci Advisor
HW Helper
P: 3,682

12.25 * 9 * pi / 4 is about 86.6, so I'd say an area of 87 or 88 square inches wouldn't be out of line. 


#7
Dec607, 06:52 PM

P: 7

Perhaps this racquet is difficult to calculate,right? http://www.tenniswarehouse.com/view...l?PCODE=RQIS1T 


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