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integrate (5x+2)dx/(x-2) from 0 to 1

 
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Dec8-07, 07:14 PM   #1
 

integrate (5x+2)dx/(x-2) from 0 to 1


1. The problem statement, all variables and given/known data

[tex]\int\frac{(5x+2)dx}{x-2}[/tex] from 0 to 1


2. Relevant equations

3. The attempt at a solution

ive tried splitting it up into (5x)/(x-2) + (2)/x-2), but i couldnt go any farter. Ived also tried using lots of U subsitutions, but i cant figure out what do next. Is there some trick that i am not seeing?
 
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Dec8-07, 07:15 PM   #2

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Yep, the obvious one. u=x-2. dx=du. x=2+u.
 
Dec8-07, 07:22 PM   #3
 
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Another way to split it up [without explicitly invoking a substitution]
is to write the numerator 5x+2 as 5(x-2)+12.
 
Dec8-07, 07:28 PM   #4
 

integrate (5x+2)dx/(x-2) from 0 to 1


Quote by robphy View Post
Another way to split it up [without explicitly invoking a substitution]
is to write the numerator 5x+2 as 5(x-2)+12.
Woah, woulda never thought of that. Nice, I want your vision :-]
 
Dec8-07, 07:38 PM   #5

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Quote by robphy View Post
Another way to split it up [without explicitly invoking a substitution]
is to write the numerator 5x+2 as 5(x-2)+12.
You'll still want u=x-2 to do the 12/(x-2) part.
 
Dec8-07, 08:00 PM   #6
 
Just do polynomial division. It becomes 5 + 12/(x - 2).

Oops.
 
Dec8-07, 08:08 PM   #7
 
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Quote by Dick View Post
You'll still want u=x-2 to do the 12/(x-2) part.
True... and now the substitution is really obvious.
 
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