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Finding resultant force 
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#1
Dec1807, 06:33 PM

#2
Dec1807, 06:45 PM

P: 3,015

I know I need to isolate a triangle, but I really suck at similar triangles when they are not necessarily right triangles.



#3
Dec1807, 06:46 PM

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P: 41,292

Draw yourself a diagram where you add the vectors (head to tail addition). The two vectors are the two sides of a triangle. You should be able to identify the angle between them and apply the law of cosines to find the third side of the triangle, which will be the resultant.



#4
Dec1807, 06:47 PM

HW Helper
P: 2,688

Finding resultant force
The 120 degree angle should be the angle corresponding to your resultant vector in the triangle. For the other angles:
HINT: What is the angle between the 80lb force and the x axis? Does this help you find another angle in your parallelogram? 


#5
Dec1807, 06:48 PM

P: 3,015

Is the angle between them by any chance 60 degrees? In the parellepgram 2(120)=240 leaving 120/2 to give me four angles that add to 360



#6
Dec1807, 06:50 PM

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P: 41,292




#7
Dec1807, 06:51 PM

P: 3,015

I'll be back in 20 minutes. All of the theological students just showed up at StarBucks and I can't take their banter.....I'm going home.
Casey 


#9
Dec1807, 07:43 PM

P: 3,015

I made it home!
Thanks Doc and G01! I am taking this Statics course over Xmass break :points gun into mouth and fake blows brains out: So is the general approach to these to use the fact that vectors can be moved around to redraw the scenario in a manner that helps to generate more information from the given info? Casey 


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