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Regarding the conversion of kinetic energy to mass |
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| Dec23-07, 02:15 AM | #1 |
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Regarding the conversion of kinetic energy to mass
According to the theory of relativity, in the case of two particles of mass m and kinetic energy k colliding, the mass of the two particles together after the collision is greater than the sum of the two particles. It is claimed that thus the kinetic energy is converted to mass. How is this so? What kind of mass appears? In what form is this mass?
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| Dec23-07, 01:45 PM | #2 |
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I think that depends on the specific particles involved. If you have a >1.1 MeV photon colliding with a nucleus then the extra mass can be in the form of an electron-positron pair. If you have two lumps of clay then the extra mass will typically be in the form of heat.
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| Dec24-07, 05:35 AM | #3 |
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| Dec24-07, 12:22 PM | #4 |
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Regarding the conversion of kinetic energy to mass |
| Dec24-07, 12:36 PM | #5 |
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| Dec24-07, 12:53 PM | #6 |
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| Dec24-07, 04:41 PM | #7 |
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| Dec24-07, 04:52 PM | #8 |
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Recognitions:
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[tex]E^2 = m^2 * c^4 + p^2 * c^2[/tex] ...where p is the object's relativistic momentum, [tex]p = \frac{mv}{\sqrt{1 - v^2/c^2}}[/tex] |
| Dec24-07, 07:44 PM | #9 |
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| Dec24-07, 11:06 PM | #10 |
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Recognitions:
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| Dec25-07, 08:49 AM | #11 |
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| Dec25-07, 09:26 AM | #12 |
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Recognitions:
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| Dec25-07, 10:11 AM | #13 |
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| Dec25-07, 12:38 PM | #14 |
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Heat is one of two modes of energy transfer; the other being work. Heat is not energy.
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| Dec31-07, 09:17 AM | #15 |
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The photons also have momentum and energy, so a "photon gas" has inertia and therefore mass. In this case the extra inertia would be due to the fact that the blue-shifted photons striking the rear of the accelerating cavity would have more momentum than the red-shifted photons striking the front.
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