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Kirchoff's Loop Rule as applied to Capacitors? |
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| Jan19-08, 08:56 AM | #1 |
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Kirchoff's Loop Rule as applied to Capacitors?
1. The problem statement, all variables and given/known data
How does the loop rule apply to capacitors? I can't find any examples of circuits containing capacitors and resistors where the loop rule is used. I know the loop rule measures potential differences, but I'm not quite sure if that has anything to do with capacitors? All the examples are 0 = V - IR - IR, etc. 2. Relevant equations 3. The attempt at a solution |
| Jan19-08, 08:59 AM | #2 |
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Yes, the loop rule is used with capacitors all the time. The element law for a capacitor is [itex]v=q/C[/itex]. In more advanced (calculus-based) courses this is written [itex]i=C\frac{dv}{dt}[/itex]. Solving this for the voltage, one obtains:
[tex]v=\frac{1}{C}\int_{t_0}^ti(\tau)d\tau+v(t_0)[/tex] |
| Jan19-08, 12:31 PM | #3 |
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all the basics of RC circuits (RL and RLC circuits too) come from a basic application of Kirchoff's Loop principle.
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| Jan20-08, 03:12 PM | #4 |
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Kirchoff's Loop Rule as applied to Capacitors?
So when finding currents, the branch that a capacitor is on (in terms of current) is 0, right? since when a capacitor is full, no current flows.
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| Jan20-08, 03:45 PM | #5 |
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not necessarily. it depends on the situation. Since charging rate = current, current=0 if and only if the charge of the capacitor is constant. This happens when the capacitor has been (dis)charging for a long time, or when the circuit reaches steady state.
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| Jan20-08, 03:49 PM | #6 |
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the problem says that the currents reach equilibrium. isn't that steady state?
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