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proving a formula |
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| Mar2-08, 07:56 PM | #1 |
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proving a formula
1. The problem statement, all variables and given/known data
Prove that if p(x)=anx^n +an-1x^n-1+..........a0, where a0,.........., "an" ε reals, is a polynomial, then p can have at most n roots. 2. Relevant equations 3. The attempt at a solution C ε R is a root of a polynomial p if p(c)=0. If c is a root of p, then x-c is a factor of p. I'm not sure where to go from here. I think it would probably be the easiest to prove this by proving the contrapositive as being false. Could someone please give me a hint or show me where to go from here? Thank you very much |
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| Mar2-08, 09:45 PM | #2 |
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Sure. Suppose the polynomial has n+1 different roots. c1,c2,...cn+1. Since c1 is a root the polynomial p(x) can be factored (x-c1)*p1(x) where p1 has degree n-1. The other c's must be roots of p1(x) since they aren't roots of (x-c1). Continue in this way until you reach degree 1. Now you have a linear polynomial with two different roots. Possible?
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| Mar2-08, 10:26 PM | #3 |
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Thank you very much
Would it be somthing like this? (p1x)^(n-1)(x-c2)(x-c3)^(n) ![]() Thank you |
| Mar2-08, 10:38 PM | #4 |
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proving a formula
No, that's not clear at all. Start by proving if n=1 then the polynomial can't have 2 roots. Ok?
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| Mar5-08, 10:10 PM | #5 |
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Thank you very much
Regards |
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