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Another CT dose related question |
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| Mar13-08, 11:47 PM | #1 |
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Another CT dose related question
Sorry for having to ask another question, but there is just one more thing that I want to get my head around.
Let's say you have this protocol: Standard Resolution 64/40 x 0.625 collimation 2.5mm thickness 40/25 mm increment 240 scan angle 0.4s rotation 120 kv 55-165 mas 512 matrix 75% prospective phase 220 DFOV approx 120 mm scan length Filter CB 100 mAs OK now here is my issue. I've been told that you can estimate effective dose by using the following formula: [tex] Effective dose = DLP * k[/tex] Now the k-factor is a normalised conversion factor and can be found at this site: http://www.drs.dk/guidelines/ct/quality/mainindex.htm ------- Appendix 1 of Chapter 1 What I don't understand is the scan angle. I thought that the CTDI and therefore the DLP were given for 360 degree scans. So therefore your estimation of effective dose (if you only use a 240 degree scan angle) wouldn't be correct if you used the above formula. For example, let's say that you performed 2 scans of the chest. For both scans you have the EXACT same protocol (same kVp and mAs) except for the scan angle. One has a scan angle of 180 degrees and one has a full 360 degree scan angle. I'm just not understanding how you can use the same formula for both these situations. I mean if you are scanning 180 degrees that is centred beneath the patient then you aren't uniformly irradiating all the organs in the chest region are you? I'm really confused about this because I just don't think that you can use that formula yet I've been told that the dose isn't dependent on the total scan angle? I hope this hasn't been to muddled of an explanation, but I'd appreciate any assistance. |
| Mar14-08, 07:48 AM | #2 |
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There's nothing in the definition of CTDI that references the scan angle. Scan angle just determines the number of projections used to reconstruct the slice.
Keep in mind that diagnostic dose estimates are just that, estimates. At best whatever number you end up with is only going to be accurate to within a factor of 2-3 at best. Most of the time, if I feel the dose estimates I calculate are within an order of magnitude, I'm happy with that. |
| Mar14-08, 09:26 PM | #3 |
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If you used a scan angle of 240 instead of 360, wouldn't you multiply your estimated DI by .66 (2/3) - because you are essentially cutting the amt of info you are collecting by approx .66?
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| Mar14-08, 09:34 PM | #4 |
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Another CT dose related question
if you're maintaining the same mAs per slice though, the mA needs to go up by 3/2 to compensate for the reduced scan time
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| Mar14-08, 09:54 PM | #5 |
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Does reducing the projections (scan angle) actually reduce the time - and visa versa?
I was under the impression that when I reduced my time, I was still getting 360 projections - just with faster rotation. If you leave the mA the same, are you're saying reducing the scan angle would not be an acceptable method of reducing dose? Normally, I would just lower my mA or time to reduce the dose. If you had a moving target (drunk) on the table would it be a good idea to up the mA and decrease the scan angle to have less chance of motion? |
| Mar15-08, 06:22 AM | #6 |
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| Mar18-08, 06:15 PM | #7 |
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Thanks, imabug!
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| Mar19-08, 04:19 PM | #8 |
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| Mar19-08, 08:10 PM | #9 |
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Strapping and taping is just a given in my job. Expecially if the patient has been drinking or appears to be on a recreational pharmaceutical of some kind.
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| Mar23-08, 08:53 AM | #10 |
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Thanks again for taking the time to explain this stuff to me Imabug.
So basically you are saying that if you have used a 240 scan angle it means that this is all the information you have used to reconstruct the slice, but you have not actually reduced dose. Even with prospective gating the tube is still "active" for the full 360 degree rotation then? I think that my main problem is that I do not have a clear visualisation of the image reconstruction in a CT system. Can you recommend any good resources regarding CTs that might clearly show this at all? |
| Mar24-08, 07:31 AM | #11 |
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you can certainly envision a CT scanner that does partial angle acquisitions by having the x-ray beam on for x degrees and then turning off for the remainding 360-x degrees. Then the radiation dose delivered depends on the constraints you set on kVp, mA and time. If you specify that the mAs is constant compared to a full 360 degree acquisition, then because the scan time is reduced mA needs to go up. Thus radiation dose remains the same. |
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