The question states:
Find the centre and radius of each circle with equations as given
(a) 3x^2 + 3y^2 = 81
(b) x^2 = 6y - y^2

I really don't know how to approach this question, i started (a) by dividing both sides by 3 but then i don't know where to go from there, and i don't even know how to do (b)...please help me
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 Mentor Well, you know that a circle with centre (p,q) and radius r can be written (x-p)2+(y-q)2=r2. (a) once you've divided through by 3, it is in the above form, isn't it? (b) try to put it in the above form by, maybe, completing the square for the y component.
 ok but cristo, for (a) you're saying that my centre would just be p and q?..no actual numbers?...and for (b) my radius would be 9? -also for (b) what would be my centre after completing the square for the y component?