Angular Acceleration Calculation: Solving Problems with Formulas | Get Help Now

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The discussion focuses on calculating angular acceleration and related parameters for a wheel with a velocity of 200 rad/min and a rotational inertia of 5500 kgm². The user successfully determined the angular acceleration to be 2.22 rad/s² and calculated the radius of the wheel to be 1.56 m using the formula I = MR². However, the user seeks assistance with calculating the time to stop the wheel under a constant torque of 10,000 Nm and the force applied, as well as the mass of the wheel, which is identified as a solid disk.

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ProSk8ter474
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Heres the problem. I'm trying to solve it at the moment, and I'll be posting what I have done so far. I'm very short on formulas for this so I will need help. Thanks a lot.

1) a) Determine angular acceleration of a wheel, which has a velocity of 200 rad/min after rotating for 1.5s from start.
b) If the wheel has a rotational inertia of 5500 kgm2(squared), what would be its radius if 5000 N of forced had been applied?
c) If the same wheel, having reached a final velocity of 200 rad/min, were slowed down with a constant torque of 10,000 NM applied (with same radius), how long would it take to stop the wheel?
d.) How much force was applied?
e.) Determine the mass of the wheel. (the wheel is a solid disk)

Again, your help would be greatly appreciated.
 
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Ok, here's what I'm thinking.

a.) (200/60)rad/min = (10/3)rad/s
Angular Acceleration = (dW/dT)
(3.33rad/s)/(1.5s) = 2.22 rad/s^2

b.) I = MR^2 F = Ma
5000N = (M)(2.22rad/s^2)
M = 2252.25 kgm/rad

I = MR^2
(5500kgm^2) = (2252.25kgm/rad)(R^2)
R = 1.56 m/rad

c.) No idea. Please Help
d.) No idea. Please Help
e.) No idea. Please Help
 
Possibility for Part C

Angular Displacement = (W^2-Wo^2)/(2*Angular Acceleration)
= (11.11rad^2/s^2)/(4.44rad/s^2)
= 2.5 rad
Angular Displacement = (t/2)(Wo+W)
=(2.5 rad) = (t/2)*(10/3rad/s)
=(2.5 rad)/(3.33rad/s)
= .75s = (t/2)
t = 1.5 s

Now, I think I solved that part, but I didn't end up using Torque or the Radius, so my answer could be wrong. Please reply with any comments
 

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