|Jun10-08, 02:01 PM||#1|
The domain of a cartesian function from parametric equations
x = 2cot t
y = (sin t)^2
t is greater than 0 but less than or equal to pi/2
The cartesian can be found using trig identities to be:
y = 8/ (4+ x^2)
What would be the range of the cartesian equation? I think it would be x is greater than or equal to 0, since when t = pi/2, x = 0, and as t tends to 0, x tends to infinity.
Am I correct?
|Jun10-08, 04:23 PM||#2|
Your title says "domain" but in the body of your message you say "range". Which is it?
If you are thinking of the "cartesian equation" as y a function of x, then the domain is the set of all possible x values which is the set of all vaues of cot(t) for t between 0 and pi/2 and the range is the set of all y values which is the set of all values of (sin t)^2 for t between 0 and pi/2.
|Jun11-08, 03:11 AM||#3|
Sorry for the confusion! I meant the domain! Would my answer therefore be correct?
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