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Hard inequalities question

by nokia8650
Tags: inequalities
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nokia8650
#1
Jun23-08, 09:47 AM
P: 228




I am having trouble with the final part of this question - part f; I can do all the previous parts. I have attached the questions and markscheme, and so woulkd appreciate it if someone could just explain part (f) to me!

Thanks alot.
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HallsofIvy
#2
Jun23-08, 10:25 AM
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Thanks
PF Gold
P: 39,294
If (f) is the part you are having trouble with, then presumably you have already proved that [itex]2x_n^2- (2n-1)x- (n+1)= 0[/itex] (part (e)). Now you want to find the smallest n such that [itex]x_n< n+ 0.05[/itex]. You could, for example, solve that using the quadrative formula and compare the solutions to n+ 0.05. Have you calculated some values of [itex]x_n[/itex]? What are [itex]x_0[/itex] [itex]x_1[/itex], etc.?
nokia8650
#3
Jun23-08, 01:20 PM
P: 228
Thanks for the help. Im still confused as to how the markscheme answers have come about which I attached above.

Thanks


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