Formula for mixing liquids of different temperatures?

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Discussion Overview

The discussion revolves around the calculation of mixing two bodies of water at different temperatures to achieve a desired final temperature. Participants explore the assumptions behind the mixing process, particularly focusing on the formula and method used for such calculations.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant presents a formula for mixing water at different temperatures, assuming a linear relationship between the volumes and temperatures of the liquids.
  • Another participant questions the precision required for the calculation, suggesting that a simple weighted-average method may suffice for practical applications.
  • A later reply indicates that the participant is primarily concerned with safety rather than precision, implying that the calculations do not need to be overly complex.
  • One participant suggests conducting a small-scale test to verify the calculations before applying them to the larger volume.

Areas of Agreement / Disagreement

Participants generally agree that the weighted-average method is a reasonable approach for this scenario, but there is some uncertainty regarding the need for precision and the potential effects of thermal expansion.

Contextual Notes

The discussion does not resolve the assumptions regarding the linearity of temperature mixing or the impact of thermal expansion on the final temperature.

Who May Find This Useful

Individuals interested in practical applications of thermodynamics, particularly in mixing liquids for temperature control, may find this discussion relevant.

kenewbie
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I'm going to fill a big container (3500 litres) with water. I'll use water from a hose, and boiled water, and I want to hit 40 degrees celsius.

Now, I figured that this was straight forward,

Temperature in hose = 10 C
Temperature of boiled water = 100 C

( 100 * X + (3500 - X) * 10 ) / 3500 = 40

Which gives 1166 litres of boiling water.

However, this assumes that 1 litre of 10 C water + 1 litre of 20 C water = 2 litres of 15 C water. In other words, that I can just add the temperatures together and then divide by the total amount of liquid.

Someone (who celsius was not able to provide a formula) said it is not as straight forward as that.. so, I'm looking for the formula for mixing liquids of different temperatures.

k
 
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How precise do you need to be? I guess you could take thermal expansion into account if you wanted to, but the simple weighted-average method you used should be good enough for most applications.
 
Oh, ok then I am golden. I only need to be accurate enough to avoid boiling anyone that ventures into the pool :)

Thanks a lot.

k
 
You could also do a test by making 3.5 liters first, using 1.17 L of boiling water.
 
Yeah, I'll do a small scale test first, to make sure.

Thanks again.

k
 

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