Thread Closed

summation involving von Mangoldt function

 
Share Thread Thread Tools
Aug3-08, 03:44 AM   #1
 

summation involving von Mangoldt function


Please help me in solving the problem,
find the sum
Sum{r=2 to infinity} (von Mangoldt(r)-1)/r



Your help is appreciated.
PhysOrg.com
PhysOrg
science news on PhysOrg.com

>> King Richard III found in 'untidy lozenge-shaped grave'
>> Google Drive sports new view and scan enhancements
>> Researcher admits mistakes in stem cell study
Aug11-08, 06:40 AM   #2
 
do you mean [tex] \sum _{n=2}^{\infty} \frac{ \Lambda (n) -1}{n} [/tex] ??


i think is divergent
Aug12-08, 01:56 AM   #3
 
hi mhill,
can you prove that the series is divergent?



-Ng
Aug12-08, 08:01 AM   #4
 
Recognitions:
Homework Helper Homework Help
Science Advisor Science Advisor

summation involving von Mangoldt function


Quote by mathslover View Post
hi mhill,
can you prove that the series is divergent?
[tex]\frac1n \sum_{k=1}^n\Lambda(k)=1+o(1/\log n)[/tex]

so your series seems to be something like

[tex]\sum\frac{1}{n\log n}\approx\log\log n[/tex]

Obviously this is very heuristic here.
Aug12-08, 09:21 AM   #5
 
Recognitions:
Homework Helper Homework Help
Science Advisor Science Advisor
OK, it diverges.

[tex]\sum_{n=2}^{\infty} \frac{\Lambda(n) -1}{n}=\sum_p\sum_{k=1}^\infty\(\frac{\log p-1}{p}+\frac{\log p-1}{p^2}+\cdots\)=\sum_p\frac{\log p-1}{p-1}[/tex]
and we all know that
[tex]\sum_p\frac1p=+\infty[/tex]
Aug13-08, 01:00 AM   #6
 
when n is a prime or prime power, the summation is okay.

but suppose when n=6, then the sum is (von Mangoldt(6) -1)/6 , which is = -1/6,

as n runs from 2 to infinity,can we settle the problem of convergency or divergency?



-Ng
Aug13-08, 08:06 AM   #7
 
Recognitions:
Homework Helper Homework Help
Science Advisor Science Advisor
Quote by mathslover View Post
when n is a prime or prime power, the summation is okay.

but suppose when n=6, then the sum is (von Mangoldt(6) -1)/6 , which is = -1/6,

as n runs from 2 to infinity,can we settle the problem of convergency or divergency?
My post addressed the case where n runs from 2 to infinity, which diverges.
Aug15-08, 01:17 AM   #8
 
Hi CRGreatHouse,

In your post 1673, the summation on LHS runs from n=2 to infinity, (n=2,3,4,5,6,7,8,...)

But the summation on RHS runs over all primes.(p=2,3,5,7,...)


From the definition of von Mangoldt function,when n=6,10,12,14,15,18,... , the summand

became (-1/n) whenever n is not equal to any prime or prime power.

Is something missing ?


-Ng
Aug15-08, 05:27 PM   #9
 
Recognitions:
Homework Helper Homework Help
Science Advisor Science Advisor
Quote by mathslover View Post
Is something missing ?
Right, right... yeah, I calculated it for numerator [itex]\Lambda[/itex] first, forgetting about the -1 term, and when I added it back in forgot that part.

But wouldn't that also suggest divergence (in the other direction), since the prime powers are density 0, the reciprocal primes vary as log log n, and the reciprocal integers vary as log n?

Numerical experimentation would be nice here.
Aug16-08, 09:10 PM   #10
 
I have tried numerical calculation and the sum seems to converge to ~ -1.16

Can we approach the problem from Zeta function?



-Ng
Thread Closed
Thread Tools


Similar Threads for: summation involving von Mangoldt function
Thread Forum Replies
Ramanujan Summation and Divergent series in relation to the Riemann Zeta function. Calculus 28
even summation with recursive function in c++ Programming & Comp Sci 1
pde involving airy function!! Calculus & Beyond Homework 0
A quotient involving Riemann function Calculus 0
Problem with limits involving a summation Set Theory, Logic, Probability, Statistics 1