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Find charge due to two particles 
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#1
Aug3008, 06:42 PM

P: 267

Suppose that the magnitude of the charge on the yellow sphere is determined to be 2q and at (d2cos(theta), d2cos(theta). Calculate the charge q_red on the red sphere at (d1,0) with a positive blue sphere,q, at the origin and whose net force,F, is in the direction of y. The yellow sphere is negative and the red sphere is positive. ( See picture bellow)
Express your answer in terms of q, d1,d2, and theta. Well the Fx on blue due to the yellow sphere= k(2q)(q)/(d2cos(theta))^2 and the Fx on blue due to the red sphere =  k(q_red)(q)/(d1)^2 Now what? I am unsure as to what to do now. Any help would be appreciated. Thank you. Stephen 


#2
Aug3008, 07:08 PM

P: 267

Would you set them equal to each other?



#3
Aug3008, 08:37 PM

P: 15

I would? because of the fact that there is no net force along the x axis. Hence all x components of the force must cancel out to equal 0. Do you not get the right answer by doing that?



#4
Aug3108, 02:51 AM

P: 267

Find charge due to two particles
I set them equal to each other and solved for q_red and got:
q_red= 2qd1^2/(d2^2)(cos(theta)^2) Did I set up the original equations correctly? And did I find q_red correctly in terms of q, d1,d2, and theta? Thank you. I really appreciate the help. Stephen 


#5
Aug3108, 05:55 PM

P: 267

I have to turn this in soon so any help would be appreciated.
thank you. Stephen 


#6
Aug3108, 09:47 PM

P: 15

I don't see anything wrong with it. Does anyone else see anything wrong with it?



#7
Sep108, 03:49 PM

P: 267

bump
Does everyone agree with novaex? Are my equations correct? 


#8
Sep108, 08:35 PM

P: 267

Not to be a bother but I have to turn this in tomorrow. So if you can please tell me whether or not I set the problem up correctly and got the correct formula for q_red: q_red= 2qd1^2/[(d2cos(theta))^2]?
Thanks I would really appreciate it. Stephen 


#9
Sep208, 12:16 AM

P: 267

Any opinions????



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