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Curved/warped space time |
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| Nov16-08, 04:17 AM | #1 |
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Curved/warped space time
Hi members,
Can someone tell me the simple analogy of curved time & space.I've searched the google but have not been able to find an A-LEVEL STUDENT stuff.I need an introductory & beginner level idea.Thanks... |
| Nov16-08, 11:13 AM | #2 |
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Have you seen the bowling ball on a stretched rubber sheet analogy? The deformation is analogous to the curving of spacetime....See Wikipedia for "Spacetime"...there is an illustration....
also try for "geodesics" for understanding how "straight lines" become "curved". Note the "SEE ALSO" section at the bottom of each of the above references for more... |
| Nov16-08, 11:20 AM | #3 |
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One thing that isn't conveyed by the bowling ball on a rubber sheet analogy is that time moves more slowly the deeper you are in a gravity well, in addition to the force of gravity being present.
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| Nov16-08, 01:23 PM | #4 |
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Curved/warped space timehttp://www.physics.ucla.edu/demoweb/...spacetime.html Longer introduction: http://fy.chalmers.se/~rico/Theses/tesx.pdf (chapter 2) Interactive visualization: http://www.adamtoons.de/physics/gravitation.swf |
| Nov16-08, 01:23 PM | #5 |
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Mentor
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Much of what you need to understand about curved spacetime can be understood by considering geometry on the surface of a sphere.
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| Feb18-09, 05:23 AM | #6 |
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I guess the fact that there is only one time dimension would mean that all clocks in the gravity wave would be effected alike whereas with space we can use the different effect on 2 space dimensions to detect a gravity wave in a LIGO. |
| Feb18-09, 08:18 AM | #7 |
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Colin.....try Wikipedia at
http://en.wikipedia.org/wiki/Gravitational_Wave for a decent discussion of gravitational waves, an illustration, and external links at the bottom. The article mentions the sun/earth gravitational wave power at 313 watts...so its REALLY weak....I assume time would be affected SLIGHTLY but so far nobdoy has even been able to unambiguously detect a gravitational wave let alone second order effects. |
| Feb18-09, 10:17 AM | #8 |
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See Shutz's book, Gravity from the Ground up |
| Feb18-09, 12:44 PM | #9 |
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In the "4D space-time" of GR time is essentially just another "direction" in which an object can move. Supposedly we just can't "see" it because we are "trapped" in a 3D perspective. So, if we consider a flexible sheet with stick figures drawn on it, and imagine that they can only move on/in the sheet itself, we can see that the inhabitants of "Flatland" have no concept of "up". They can only see directly in front, behind, and to the side of them, but never "up". In this analogy our "dimension" of "time" is similar to the Flatlander's "up". Now lets say there is a deep depression in the sheet and a Flatlander is down in it. There's another Flatlander outside, in the flat area, watching the trapped one. As the trapped one travels out of the depression s/he is mostly moving "up" instead of across. So, while the trapped Flatlander is making considerable total progress in THREE dimensions, most of it is in the "up" direction which the observer and the trapped cannot perceive. Therefore the observer sees the trapped Flatlander moving very slowly (just a little bit "across" but a lot "up"). As the trapped one escapes the depression the sheet becomes less and less vertical and the outside observer sees him accelerating (he moves more "across" and less "up"). The trapped one could have been moving the exact same speed (in 3 dimensions) all along but because the Flatlanders can't see one of them, they are deceived. This analogy isn't quite there yet, because in addition to simply moving in an unseeable "up" (or time) direction, the surface on which the trapped Flatlander is moving is stretched. If before the surface was flat with a surface area A, and we placed an object (a circle?) somewhere and caused a depression, we now have a total surface area B>A. So the trapped flatlander not only appears to move more slowly because of his/her progression in an unseeable direction, but actually does move more slowly because the sheet itself is stretched out (a "meter" is "further" now than before). |
| Feb20-09, 08:11 PM | #10 |
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Curved space-time slows clocks ie clocks slow in a gravitational field (as compared with clocks out of the gravity field) That is what makes me think that a gravity wave should slow a clock. Colin |
| Mar13-09, 06:37 PM | #11 |
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| Mar18-09, 03:39 PM | #12 |
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As i understand it with the rubber sheet bowling ball analogy gravity is due to the curvature of time and not due to a force is that right?
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| Mar18-09, 04:02 PM | #13 |
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http://www.physicsforums.com/showpos...92&postcount=4 |
| Mar18-09, 04:12 PM | #14 |
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if gravity is due to curved time I take it moving towards a mass does not involve work (ie no energy is expended by either mass) as there is no force involved ?
But if this is the case how come moving away from a mass does involve work? |
| Mar18-09, 04:40 PM | #15 |
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| Mar18-09, 05:14 PM | #16 |
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If a meteorite is moving in a straight line(ie direct hit) towards the earth then is it following a geodiesic path? I say it must be as no external force is acting on the merteorite and it is simply following curved time. Therefore do you agree a straight line is a geodiesic path? Assuming you agree with the above from your logic if a meteorite (M) moves towards earth (E) following a geodeisc path, energy expended by E = 0 energy expended by M = 0 if a meteorite (M) moves towards earth (E) following a striaght line (ie direct hit) as a striaght line is a geodiesic, energy expended by E = 0 energy expended by M = 0 Now if I move a meteorite (M) AWAY from the earth (E) along a geodeisc path energy expended by E = 0 energy expended by M = 0 energy expended by me = 0 and if I move a meteorite (M) AWAY from the earth (E) in a striaght line (ie a line perpendicular to a 2d tangential plane to the surface of the earth), as a striaght line is a geodeisic path, you are saying energy expended by E = 0 energy expended by M = 0 energy expended by me = 0 I disagree if I move a meteorite (M) or anything for that matter AWAY from the earth (E) in a striaght line (ie a line perpendicular to a 2d tangential plane to the surface of the earth) then energy will be expended and energy expended by E = 0 energy expended by M = 0 energy expended by me > 0 Further I contend if I move any mass away from any other mass along any path, as long as the nett distnace between the two massess is increasing, then energy will be expended |
| Mar18-09, 06:21 PM | #17 |
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- The path of the meteorite in space, which is a line - The path of the meteorite in spacetime, which is a geodesic For the free fall case they are both geodesics, but not for the lift case: |
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