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commutate relation of lowering operator and sperical tensor operators |
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| Dec8-08, 06:06 PM | #1 |
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commutate relation of lowering operator and sperical tensor operators
Hi all,
I found a commutation relation of lowering operator(J-) and spherical operator in Shankar's QM (2ed, page 418, Eq 15.3.11): [tex][J_-,T_k^q] = - \hbar \sqrt{(k+q)(k-q+1)} T_k^{q-1}[/tex] I wonder how the minus sign in the begining of the right hand side come out? I have googled some pages, some of them have that "-", e.g. : http://galileo.phys.virginia.edu/cla...rOperators.htm the formula appears at the end of this page. and some has no "-", e.g.: http://atoms.vuse.vanderbilt.edu/Ele...HF/node30.html Eq(116) at the begining . I also found there's no minus in Messiah's QM (Vol II, page 572, Eq XIII.123a) [tex][J_-,T_q^{(k)}] = \sqrt{k(k+1)-q(q-1)} T_{q-1}^{(k)}[/tex] So, the question is which one is correct? Thanks :) |
| Dec9-08, 10:32 AM | #2 |
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Recognitions:
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Both are correct. It depends on the convention adopted for the T operators. In particular, for a vector operator, it depends on whether [tex]T^{\pm 1}_1 = x\pm iy[/tex] or [tex]T^{\pm 1}_1 = \pm(x\pm iy)[/tex].
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