
#1
Feb1009, 10:27 PM

PF Gold
P: 125

Does a charged particle at rest (m_{0}>0) have more total energy than an uncharged particle with the same rest mass at rest? Thanks in advance.




#2
Feb1109, 08:17 AM

Sci Advisor
P: 1,250

The energy of a single particle depends only on its mass.
Any EM energy of a charged particle is already included in its mass. 



#3
Feb1409, 03:55 PM

P: 1,160

If the EM energy is included into the mass, it contributes to it, right? Then what does contribute to the mass of a neutral particle of the same mass?




#4
Feb1509, 09:00 PM

PF Gold
P: 125

Energy of Electrostatic Charge ? 



#5
Feb1509, 10:58 PM

P: 1,772

A single charged particle has (classically) infinite self energy: that is what you get from integrating the energy density over a spherical volume and letting the volume shrink to zero.
If you now bring in a second charge at a finite nonzero distance from the first one, there is a finite "interaction energy" for this twocharge system  it is just the work done in bringing the second charge in from infinity to this finite location, in the field created by the first charge. Of course, the self energy of each charge is still infinite. (You can look upon the infinite self energy of a point charge as the energy required to create a charge out of "free space". We don't know how exactly we could do this, and I don't know if this is really a very good way to look at this idea, but it is at least intuitive classically.) So to summarize, 1. the total energy of the point charge is the sum of its rest energy (by virtue of its mass) and its self energy (which is infinite). 2. for an uncharged particle, the total energy is just the rest energy. (Caveat: an uncharged "mass" can be considered consist of equal positive and negative point charges, each of which should  by the above argument  have an infinite amount of self energy. We therefore need more justification for point 2.) 



#6
Feb1609, 05:35 AM

P: 1,160

>A single charged particle has (classically) infinite self energy: that is what you get from >integrating the energy density over a spherical volume and letting the volume shrink to >zero.
The classical notion of pointlike particle is not "fundamental" but illusive: it corresponds to the inclusive picture where different observations (inelastic events) are added up (see my work at arxiv:0806.2635 or Central European Journal of Physics, Volume 7, pp. 111, 2009, “Atom as a dressed nucleus”). Concerning the mass renormalizations, see my another work at arxiv:0811.4416, “Reformulation instead of renormalizations”. Quantum mechanically any charge is smeared since it makes part of the EM field oscillators. So there is no problem of the selfenergy divergence. Regards, Bob. 



#7
Feb1609, 11:41 AM

P: 1,772





#8
Feb1609, 01:06 PM

P: 1,160

Yes, I mean exactly that. The formalism is simple and it uses another, quite natural approach.
You know, the selfaction term jA was introduced by H. Lorentz by analogy with electron interaction with external fields. Lorentz wanted to add some "friction" term for the sake of the energymomentum conservation. In fact, there is another way of the electronfield coupling preserving the energymomentum. My papers are accessible at arXiv and they are intentionally made as simple as possible for understanding. Start from "Atom as a dressed nucleus". You will see immediately the quantum mechanical effects of binding. Then read "Reformulation instead of Renormalizations" where the "selfaction" ansatz is replaced with the "interaction" ansatz. The latter eliminates the problem of divergences. Regards, Bob. 


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