## Parallel Plate Capacitance

A capacitor with capacitance of C = 8.5±1 μF has a potential difference of V = 4.5±0.4 Volts. What are the charge on the capacitor and the error in this value, in μC?

To find charge I just use Q = C*V correct? And how do I calculate the error?

Thank you!
 PhysOrg.com science news on PhysOrg.com >> City-life changes blackbird personalities, study shows>> Origins of 'The Hoff' crab revealed (w/ Video)>> Older males make better fathers: Mature male beetles work harder, care less about female infidelity
 Recognitions: Homework Help For s=ab $$\frac{\delta s }{s}= \frac{\delta a}{a} + \frac{\delta b}{b}$$ Where $\delta s$ is the error in s and similiarly for a and b.
 Recognitions: Homework Help Another way to say that is that for multiplying and dividing, the % errors in quantities are added.

 Similar discussions for: Parallel Plate Capacitance Thread Forum Replies Introductory Physics Homework 1 Introductory Physics Homework 12 Classical Physics 1 Introductory Physics Homework 16