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Parallel Plate Capacitance |
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| Feb13-09, 06:26 PM | #1 |
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Parallel Plate Capacitance
A capacitor with capacitance of C = 8.5±1 μF has a potential difference of V = 4.5±0.4 Volts. What are the charge on the capacitor and the error in this value, in μC?
To find charge I just use Q = C*V correct? And how do I calculate the error? Thank you! |
| Feb13-09, 08:36 PM | #2 |
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Recognitions:
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For s=ab
[tex]\frac{\delta s }{s}= \frac{\delta a}{a} + \frac{\delta b}{b}[/tex] Where [itex]\delta s[/itex] is the error in s and similiarly for a and b. |
| Feb13-09, 08:41 PM | #3 |
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Recognitions:
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Another way to say that is that for multiplying and dividing, the % errors in quantities are added.
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