Register to reply

Hooke's Law Sample Problems

by meikamae
Tags: hooke, sample
Share this thread:
meikamae
#1
Jun12-03, 08:29 PM
P: n/a
I need a sample problem (and solution, please) for hooke's law to help me understand. I understand the equation, I just don't understand what the variables mean exactly and how the equation works and what each variable stands for.
Phys.Org News Partner Science news on Phys.org
Climate change increases risk of crop slowdown in next 20 years
Researcher part of team studying ways to better predict intensity of hurricanes
New molecule puts scientists a step closer to understanding hydrogen storage
schwarzchildradius
#2
Jun13-03, 02:08 AM
schwarzchildradius's Avatar
P: 179
ok, Hooke's law applies to the idealized case of a spring. The further you stretch the spring, the greater the force opposing the stretching, in other words, it assumes that the force increases linearly with distance.
F = -kx
where k is the spring constant, F is the force generated by the spring, x is the displacement from equilibrium (where F=0). Any basic sample problem will require the equation re-arranged; or substitution of another variable into the two changable variables, x and F; or balance the equation with another force (say, a mass on a spring so that F = mg).
You could also ask to determine the velocity and KE of the spring at any time or displacement of x. Or you could find the general solution to the differential equation of a harmonic oscillator, which is what you've got with a mass on a spring, and find sinusoidal motion in space, decaying exponentially with the damping constant. So it depends on what depth you need.
HallsofIvy
#3
Jun13-03, 07:36 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,323
Hook's law is this: F= kx where F is the force applied to stretch or compress the spring, x is the distance the spring is stretched or compressed and k is the "spring constant". It basically says that the response of a spring is proportional to the force.

Your text may have F= -kx. The difference here is that F now is the force exerted BY the spring rather than the force exerted ON the spring ("equal and opposite").

Here are several "Hook's law" problems.

A spring with spring constant .4 cm/dyne has a force of 40 dynes applied to it (stretching it). How much does the spring stretch?

A force of 600 Newtons will compress a spring 0.5 meters. What is the spring constant of the spring?

A spring has spring constant 0.1 m/Newton. What force is necessary to stretch the spring by 2 meters?

A force of 40 Newtons will stretch a spring 0.1 meter. How far will a force of 80 Newtons stretch it?


Register to reply

Related Discussions
Sample Dynamics Problems with solutions? Mechanical Engineering 4
Sample Problems Calculus & Beyond Homework 1
I need sample problems in applied mechanics Engineering, Comp Sci, & Technology Homework 0
Best Place To Find Loads of Sample Physic Problems (grade 12) Academic Guidance 2
MOMENTUM and IMPULSE sample problems and solutions Introductory Physics Homework 2