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What is the mass of the ionby shimizua
Tags: mass 
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#1
Mar909, 07:35 PM

P: 100

1. The problem statement, all variables and given/known data
A mass spectrometer applies a voltage of 2.00 kilovolts to accelerate a singly charged ion (+e). This ion then enters a region of uniform magnetic field (B= 0.400 T) which then bends the ion into a circular path of radius 0.305 m What is the mass of the ion? 2. Relevant equations after breaking everything down from F=ma i got to m = (qB^2r^2)/2V 3. The attempt at a solution well i am just unsure of how to find q. I know that V=2kV, B=.4 T, and r=.305 m. so if you can just help me with finding q. i can do that rest 


#2
Mar909, 09:11 PM

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P: 5,341



#3
Mar909, 09:41 PM

P: 100

ok well so i tried doing the m= 1.602x10^19(.4^2)(.305^2)/4 and got 5.96x10^22. would it be in kg though?



#4
Mar909, 10:12 PM

HW Helper
P: 5,341

What is the mass of the ion



#5
Mar909, 11:09 PM

P: 1

The conundrum you got going here is that the charge is +e, not e. SOO...in taking your big step in finally realizing that q is given as the charge +e, you can now go figure that the charge is POSITIVE (1.6*10^19 C), not negative.



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