Quantum Mechanics Question 1-D Well

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SUMMARY

The discussion centers on calculating the length of quantum wires modeled as a 1-D infinite potential well, specifically using the longest absorbed wavelength of 0.44 mm. The correct length of each wire is established as 20 nanometers. The user initially calculated the energy absorbed using the formula E = hc/λ, resulting in an energy value of approximately 0.0028182 eV, but misapplied the energy equation for the potential well, leading to an incorrect length of 11.555 nm. The discrepancy highlights the importance of correctly applying quantum mechanics equations in problem-solving.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically 1-D infinite potential wells.
  • Familiarity with the energy quantization formula En = (h^2/(8mL^2))n^2.
  • Knowledge of the relationship between energy, wavelength, and frequency (E = hc/λ).
  • Basic proficiency in unit conversions, particularly between nanometers and millimeters.
NEXT STEPS
  • Review the derivation and application of the energy quantization formula for 1-D potential wells.
  • Study the implications of wavelength and energy in quantum mechanics, focusing on light-matter interactions.
  • Explore advanced topics in quantum mechanics, such as the Schrödinger equation and its applications to potential wells.
  • Practice additional problems involving quantum wires and potential wells to reinforce understanding of the concepts.
USEFUL FOR

Students and educators in physics, particularly those studying quantum mechanics and its applications in nanotechnology and materials science.

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Homework Statement



Light of various wavelengths is shined on a collection of "quantum wires" all of the same length. Each 'wire' consists of an electron trapped in a carbon nanotube, which we approximate as a 1-D infinite potential well of a width equal to the length of the wire.

It is observed that the longest wavelength that is absorbed by the collection of wires (corresponding to an electronic excitation in each wire), is 0.44 mm. What is the length of each wire?


Homework Equations



En = (h^2/(8mL^2))n^2
E = hc/lamda

The Attempt at a Solution



Ok, so I actually know the answer to this question. It is 20 nanometers. I can't figure out what I'm doing wrong, though. Here is what I did:

First calculate the energy being absorbed:

E = hc/lamda = 1240 / (.44*10^6) = .0028182

Then I use that to find L, the length of the wire (width of the potential well):

E1 = (h^2/(8mL^2))1^2
L^2 = (1.505/(4*.0028182))
L = (1.505/(4*.0028182))^.5 = 11.555 nm

The answer should be 20 nm, where and how did I go wrong?
 
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Did I post this in the wrong forum? I see a lot of quantum mechanics in the advanced physics forum.
 

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