- #1
kurious
- 633
- 0
If the universe is a simple harmonic oscillator then it must be symmetrical and divided into two halves , each half with approximately 10^52 kg of mass at its centre of mass.
If the universe reaches about 10^26 metres in about 10^18.5 seconds
then using E = ( n + 1/2)h w for an oscillator we get E = 10^-34 x 10^ -18.5 = 10^-52.5 Joules for the ground state.Since we are in the accelerating phase of the oscillator ( which is heading towards the bottom of a parabola formed by plotting potential energy against extension from equilibrium) it is losing potential energy in steps and the minimum it loses is 10^ - 52.5 Joules.
This is the amount of kinetic energy per step that dark energy could gain, increasing its relativistic mass and keeping its density constant per unit volume as the universe expands.
The universe probably loses potential energy by passing energy from gravitons to dark energy.The oscillator is quantised and so this means the gravitons must be also - the gravitons must lose energy in quanta.
If the universe reaches about 10^26 metres in about 10^18.5 seconds
then using E = ( n + 1/2)h w for an oscillator we get E = 10^-34 x 10^ -18.5 = 10^-52.5 Joules for the ground state.Since we are in the accelerating phase of the oscillator ( which is heading towards the bottom of a parabola formed by plotting potential energy against extension from equilibrium) it is losing potential energy in steps and the minimum it loses is 10^ - 52.5 Joules.
This is the amount of kinetic energy per step that dark energy could gain, increasing its relativistic mass and keeping its density constant per unit volume as the universe expands.
The universe probably loses potential energy by passing energy from gravitons to dark energy.The oscillator is quantised and so this means the gravitons must be also - the gravitons must lose energy in quanta.