Deuterium fusion into Helium-4

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    Deuterium Fusion
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Discussion Overview

The discussion centers on the fusion of deuterium into helium-4, exploring why deuterium does not directly fuse into helium-4 but instead produces tritons, helions, protons, or neutrons. Participants examine the underlying processes, including nuclear spin, energy conservation, and the role of photon emission in fusion reactions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants suggest that deuterium's nuclear spin (+1) prevents it from fusing directly into helium-4 (spin 0), while combinations like tritium and proton or helium-3 and neutron fit better.
  • There is a discussion about the conservation of energy and momentum, with some arguing that fusion must involve two particles going to two or more particles.
  • Questions are raised regarding the possibility of the reaction d+d → He-4 + γ occurring, with some participants noting that emitting a photon introduces a suppression factor compared to other fusion processes.
  • Muon-catalyzed fusion is mentioned as a process that can result in the formation of alpha particles, indicating that different conditions may lead to different fusion outcomes.
  • Participants express curiosity about the relative probabilities of various fusion reactions involving deuterium, tritium, and helium-3, particularly in the context of astrophysical environments like brown dwarfs.
  • There is a mention of a recent paper discussing alternative universes with varying levels of deuterium and its implications for stellar fusion.

Areas of Agreement / Disagreement

Participants express differing views on the mechanisms and probabilities of deuterium fusion, with no consensus reached on the direct fusion into helium-4 or the significance of photon emission in the process.

Contextual Notes

Limitations include the dependence on nuclear spin definitions, the complexity of energy conservation in fusion processes, and the unresolved nature of the reactions discussed.

qraal
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Hi All

Just wondering why does deuterium fused with itself not make helium-4 - instead it makes a triton or a helion and a proton or a neutron. These products could then fuse with deuterium to make helium-4.

What stops deuterium from fusing straight into alpha particles? Is the kinetic energy too high for it to stick together as a whole or is it driven by a more exotic process?
 
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Hi there,

I could be mistaking, but the reason for deuterium not fusing into helium-4 come from the nuclear spin. Deuterium has a nuclear spin of +1, and helium-4 has a spin of 0. Then again, both combination of tritium (+1/2) + proton (+1/2) or helium-3 (+1/2) + neutron (+1/2) fit well.

Cheers
 
but spin 1 coupled to spin 1 can give spin 2,1 or 0 as final state.
 
In order to conserve both energy and momentum, fusion can only occur with two particles going to two (or more) particles.
 
qraal said:
What stops deuterium from fusing straight into alpha particles?

What makes you think the reaction d+d \rightarrow {\rm{^4He}} + \gamma doesn't occur?
 
clem said:
In order to conserve both energy and momentum, fusion can only occur with two particles going to two (or more) particles.

How do you explain neutron capture then? E.g. Au-197 + n -> Au*-198
 
Vanadium 50 said:
What makes you think the reaction d+d \rightarrow {\rm{^4He}} + \gamma doesn't occur?
Emitting a photon brings in a factor of alpha=1/137 compared topurely strong processes.
 
QuantumPion said:
How do you explain neutron capture then? E.g. Au-197 + n -> Au*-198
The key there is the star. When states of finite width are involved there can be absorption of neutrons with energies within the width of the excited state. That can't happen with
d+d-->He, all of which are stable.
 
So any definite answers? Guys?
 
  • #10
  • #11
I believe clem is correct, there's nothing to carry away extra energy unless you go electromagnetic (d + d -> He4 + gamma) and that process is suppressed by the factor of 1/137 compared to d + d -> He3 + n and d + d -> t + p.
 
  • #12
Well that makes sense. The case of muonium fusion doesn't change that because the muon is another particle in the mix.

What's the relative fusion probabilities of d+d and d+t and d+He3 then? Obviously it depends on the abundance of d, but how much easier or harder are the other two reactions when both the t and He3 are being made from the d+d reaction?

I'm wondering just how hot the core of a brown dwarf star gets in order to burn deuterium, which must be pretty easy to do (inside brown dwarfs I mean) since it's only 1/6000th of the hydrogen available.

A recent paper on the Anthropic Principle (do you want me to drag out a reference?) discussed alternative Universes with higher levels of deuterium. What if a star was mostly deuterium? How light would it be and still achieve fusion?


hamster143 said:
I believe clem is correct, there's nothing to carry away extra energy unless you go electromagnetic (d + d -> He4 + gamma) and that process is suppressed by the factor of 1/137 compared to d + d -> He3 + n and d + d -> t + p.
 
  • #13
clem said:
Emitting a photon brings in a factor of alpha=1/137 compared topurely strong processes.

That doesn't prevent the reaction from occurring.
 
  • #14
But it is not d+d-->He, which I thought was the original question.
 

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