| Thread Closed |
Proving converse of fundamental theorem of cyclic groups |
Share Thread | Thread Tools |
| May7-09, 08:59 AM | #1 |
|
|
Proving converse of fundamental theorem of cyclic groups
1. The problem statement, all variables and given/known data
If G is a finite abelian group that has one subgroup of order d for every divisor d of the order of G. Prove that G is cyclic. 2. Relevant equations 3. The attempt at a solution |
| May7-09, 02:56 PM | #2 |
|
|
Post what you've done on this problem please.
|
| May7-09, 03:31 PM | #3 |
|
Recognitions:
|
Can you check the question. C_2 x C_2 has subgroups of orders 1,2 and 4, but is not cyclic.
|
| May7-09, 03:58 PM | #4 |
Recognitions:
|
Proving converse of fundamental theorem of cyclic groups |
| May8-09, 01:12 AM | #5 |
|
Recognitions:
|
And that's why we have the word 'exactly'.
|
| Thread Closed |
| Thread Tools | |
Similar Threads for: Proving converse of fundamental theorem of cyclic groups
|
||||
| Thread | Forum | Replies | ||
| The converse and proving whether or not the converse holds | Linear & Abstract Algebra | 1 | ||
| converse of mean value theorem? | Calculus | 2 | ||
| is there a converse of uniqueness theorem | Classical Physics | 10 | ||
| Is anyone familiar with Converse to Rouche's Theorem? | Calculus | 9 | ||
| van Kampen's theorem and fundamental groups | General Math | 7 | ||