Calculate Height of Object in 9 secs

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Discussion Overview

The discussion revolves around calculating the height an object reaches when launched, given that it travels up and back down, landing after 9 seconds. The focus is on the application of kinematic equations in the context of projectile motion under the influence of gravity.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant seeks assistance in determining the height of an object launched and landing after 9 seconds, noting the symmetry of travel time in a vacuum.
  • Another participant emphasizes the importance of understanding the acceleration due to gravity, approximately 9.8 m/s², suggesting that this knowledge is crucial for solving the problem.
  • A third participant welcomes the original poster and suggests using standard constant acceleration equations to approach the problem.
  • A link to a resource on kinematic equations is provided, which may contain relevant information for solving the problem.

Areas of Agreement / Disagreement

Participants generally agree on the relevance of kinematic equations and the significance of gravitational acceleration, but no consensus on a specific solution or method has been reached.

Contextual Notes

The discussion does not clarify specific assumptions regarding air resistance or the initial velocity of the object, which may affect the calculations.

charles7
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I need help. I need to know how high an object goes if launched, travels up and back down, and lands 9 seconds later. I remember that in a vacuum, the travel time up equals the travel time down, but what is the equation?
 
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The only thing you need to know, other than some basic algebra, is that the acceleration due to gravity is ~9.8 m/s2. Think about what that unit really means and it should be easy to solve.
 
Welcome to PF!

Hi charles7! Welcome to PF! :wink:

Use the standard constant acceleration equations. :smile:
 

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